6. The line segment PQ, where P is the point (7, 7) and Q the point (-1, 3), is the diameter of a circle. The equation of the circle is A (x – 7)(x + 1) + (y – 7)(y – 3) = 0 B (x – 7)(x – 1) + y– 7)(y– 3) = 0 C (x+7)(x – 1) + (y + 7)(y + 3) = 0 D (x + 7)(x + 1) + (y – 7)y + 3) = 0
6. The line segment PQ, where P is the point (7, 7) and Q the point (-1, 3), is the diameter of a circle. The equation of the circle is A (x – 7)(x + 1) + (y – 7)(y – 3) = 0 B (x – 7)(x – 1) + y– 7)(y– 3) = 0 C (x+7)(x – 1) + (y + 7)(y + 3) = 0 D (x + 7)(x + 1) + (y – 7)y + 3) = 0
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![6. The line segment PQ, where P is the point (7, 7)
and Q the point (-1, 3), is the diameter of a
circle. The equation of the circle is
A (x – 7)(x + 1) + (y – 7)(y – 3) = 0
B
(x – 7)(x – 1) + y– 7)(y– 3) = 0
C (x+7)(x – 1) + (y + 7)(y + 3) = 0
D (x + 7)(x + 1) + (y – 7)y + 3) = 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F09e324cc-209a-4a6d-90d1-94f0dbf2529c%2F5371c5c8-23d1-4827-8d13-5c0d3c96a7f1%2Fc06enu_processed.png&w=3840&q=75)
Transcribed Image Text:6. The line segment PQ, where P is the point (7, 7)
and Q the point (-1, 3), is the diameter of a
circle. The equation of the circle is
A (x – 7)(x + 1) + (y – 7)(y – 3) = 0
B
(x – 7)(x – 1) + y– 7)(y– 3) = 0
C (x+7)(x – 1) + (y + 7)(y + 3) = 0
D (x + 7)(x + 1) + (y – 7)y + 3) = 0
![When f(x) = 2x3 + x² – 13x + 6 is divided
by 2x – 1, the remainder is
7.
A 13
в 52
D- 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F09e324cc-209a-4a6d-90d1-94f0dbf2529c%2F5371c5c8-23d1-4827-8d13-5c0d3c96a7f1%2Fnpn5yp_processed.png&w=3840&q=75)
Transcribed Image Text:When f(x) = 2x3 + x² – 13x + 6 is divided
by 2x – 1, the remainder is
7.
A 13
в 52
D- 0
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