= 6. The lifetime, in years, of an air compressor is an exponentially distributed random variable T with mean u. If the compressor is defective, its lifetime, Ta, has u 0.1 whereas if the compressor is not defective, its lifetime Tnd has mean = 1. Twenty percent of compressors are defective. [Recall that an exponential random variable with mean u has probability density function f(t) = exp{-} for t > 0.] (a) Let D(t) denote the conditional probability that a compressor is defective, given that it fails after t years of usage. Show that D(t) = 5 5+2e⁹t

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=
6. The lifetime, in years, of an air compressor is an exponentially distributed random variable
T with mean . If the compressor is defective, its lifetime, Ta, has u : 0.1 whereas if the
compressor is not defective, its lifetime Tnd has mean = 1. Twenty percent of compressors
are defective. [Recall that an exponential random variable with mean u has probability density
function f(t) = exp{-} for t > 0.]
μ
(a) Let D(t) denote the conditional probability that a compressor is defective, given that it
fails after t years of usage. Show that
D(t)
=
5
5+2e⁹t
Transcribed Image Text:= 6. The lifetime, in years, of an air compressor is an exponentially distributed random variable T with mean . If the compressor is defective, its lifetime, Ta, has u : 0.1 whereas if the compressor is not defective, its lifetime Tnd has mean = 1. Twenty percent of compressors are defective. [Recall that an exponential random variable with mean u has probability density function f(t) = exp{-} for t > 0.] μ (a) Let D(t) denote the conditional probability that a compressor is defective, given that it fails after t years of usage. Show that D(t) = 5 5+2e⁹t
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