6. The Islamic geometers investigated solutions to cubic equations. During the period of 900-1100 AD, they investigated solutions using the intersection of two conics. For example, Omar Khayyam, who lived from 1050 to 1130 AD, classified the cubic equations into 14 types. For example, he constructed the solution to x³ + x = 4 as follows: ². For your where the semicircle has equation (x - 2)² + y² = 4 and the parabola has equation y = information, the numerical solution, which the Islamic mathematicians did not know how to find, is: X 18+√327 32/3 X = 1 3(18+√327) Prove that the intersection of the two equations reduces to the equation x³ + x = 4. 3 ≈ 1.379.

6. The Islamic geometers investigated solutions to cubic equations. During the period of 900-1100 AD, they investigated solutions using the intersection of two conics. For example, Omar Khayyam, who lived from 1050 to 1130 AD, classified the cubic equations into 14 types. For example, he constructed the solution to x³ + x = 4 as follows: ². For your where the semicircle has equation (x - 2)² + y² = 4 and the parabola has equation y = information, the numerical solution, which the Islamic mathematicians did not know how to find, is: X 18+√327 32/3 X = 1 3(18+√327) Prove that the intersection of the two equations reduces to the equation x³ + x = 4. 3 ≈ 1.379.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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