6. Suppose the student performs the experiment in the previous problem, what is the percent yield if they generate 0.565g of CaCO3?

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Chapter1: Chemical Foundations
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Please help with question 6
### Educational Exercise: Calculating Chemical Yields

#### Instructions:

1. **Calculate Mass of Sodium Carbonate:**
   - To prepare a Sodium Carbonate (Na₂CO₃) solution from 100 mL of a 0.750 M solution, determine the mass required.
   - **Solution:**
     \[
     \frac{100 \text{ mL}}{1000 \text{ mL/L}} \times 0.750 \text{ mol/L} = 0.075 \text{ mol}
     \]
     \[
     \text{Na}_2\text{CO}_3 = 106 \text{ g/mol}
     \]
     \[
     \text{Mass of Na}_2\text{CO}_3 = 106 \text{ g/mol} \times 0.075 \text{ mol} = 7.95 \text{ g}
     \]

2. **Calculate Mass of Calcium Chloride:**
   - To prepare a 0.250 M solution of CaCl₂ from 100 mL of solution, determine the mass of Calcium Chloride required.
   - **Solution:**
     \[
     0.250 \text{ m} \times \frac{100 \text{ mL}}{1000 \text{ mL/L}} = 0.025 \text{ mol}
     \]

3. **Calculate Theoretical Yield of Calcium Carbonate:**
   - If using 10.0 mL of Sodium Carbonate solution with an excess of Calcium Chloride, determine how many grams of Calcium Carbonate should be theoretically produced.
   - **Reaction:** 
     \[
     \text{Na}_2\text{CO}_3 + \text{CaCl}_2 \rightarrow \text{CaCO}_3 + 2\text{NaCl}
     \]

4. **Calculate Yield from Calcium Chloride Solution:**
   - Using 25.0 mL of Calcium Chloride solution and an excess of Sodium Carbonate, calculate the theoretical yield of Calcium Carbonate.

5. **Determine Combined Theoretical Yield:**
   - Using results from steps 3 and 4, find the theoretical yield when 25.0 mL of a 0.250 M solution of CaCl₂ is mixed with 10.0 mL of a 0.750 M Sodium Carbonate solution.

6
Transcribed Image Text:### Educational Exercise: Calculating Chemical Yields #### Instructions: 1. **Calculate Mass of Sodium Carbonate:** - To prepare a Sodium Carbonate (Na₂CO₃) solution from 100 mL of a 0.750 M solution, determine the mass required. - **Solution:** \[ \frac{100 \text{ mL}}{1000 \text{ mL/L}} \times 0.750 \text{ mol/L} = 0.075 \text{ mol} \] \[ \text{Na}_2\text{CO}_3 = 106 \text{ g/mol} \] \[ \text{Mass of Na}_2\text{CO}_3 = 106 \text{ g/mol} \times 0.075 \text{ mol} = 7.95 \text{ g} \] 2. **Calculate Mass of Calcium Chloride:** - To prepare a 0.250 M solution of CaCl₂ from 100 mL of solution, determine the mass of Calcium Chloride required. - **Solution:** \[ 0.250 \text{ m} \times \frac{100 \text{ mL}}{1000 \text{ mL/L}} = 0.025 \text{ mol} \] 3. **Calculate Theoretical Yield of Calcium Carbonate:** - If using 10.0 mL of Sodium Carbonate solution with an excess of Calcium Chloride, determine how many grams of Calcium Carbonate should be theoretically produced. - **Reaction:** \[ \text{Na}_2\text{CO}_3 + \text{CaCl}_2 \rightarrow \text{CaCO}_3 + 2\text{NaCl} \] 4. **Calculate Yield from Calcium Chloride Solution:** - Using 25.0 mL of Calcium Chloride solution and an excess of Sodium Carbonate, calculate the theoretical yield of Calcium Carbonate. 5. **Determine Combined Theoretical Yield:** - Using results from steps 3 and 4, find the theoretical yield when 25.0 mL of a 0.250 M solution of CaCl₂ is mixed with 10.0 mL of a 0.750 M Sodium Carbonate solution. 6
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percent yield = observed yield Theoretical yield * 100

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