6. Solve the following problem: kiwis cost 5 coins, oranges cost 4 coins, and 2 grapes together cost a coin. How many kiwis, oranges, and grapes totaling 100 can be bought for 100 coins? Assume no fractional parts of a banana, orange, or grape can be bought. There are two solutions.
6. Solve the following problem: kiwis cost 5 coins, oranges cost 4 coins, and 2 grapes together cost a coin. How many kiwis, oranges, and grapes totaling 100 can be bought for 100 coins? Assume no fractional parts of a banana, orange, or grape can be bought. There are two solutions.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter7: Applying Fractions
Section7.7: Mixture Problems
Problem 1P
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![6. Solve the following problem: kiwis cost 5 coins, oranges cost 4 coins, and 2 grapes together cost a
coin. How many kiwis, oranges, and grapes totaling 100 can be bought for 100 coins? Assume no
fractional parts of a banana, orange, or grape can be bought. There are two solutions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd29d4910-b472-4235-a6b7-3ae9df233500%2Fe23e1e30-b315-4da2-abd4-45db99c63a29%2Fxmvsww_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Solve the following problem: kiwis cost 5 coins, oranges cost 4 coins, and 2 grapes together cost a
coin. How many kiwis, oranges, and grapes totaling 100 can be bought for 100 coins? Assume no
fractional parts of a banana, orange, or grape can be bought. There are two solutions.
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