6. Since 3 is a constant, use the following property of summation to find the sum 3i- | = 1 E ka; = kEa; 1 = 1 | = 1 Using the above property, 6. 3i = T= 1 |= 1 56 x (1 + 2 +3 %3D + 4 + 5+ 6) X (21) %3D Hence, 3i =126 1= 1 IM-

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