6. Show that when 0 < |-1|< 2, (z-1)(z-3) Complex Analysis (z-1)" 2+2 =-36 z−3) ² A=0 2(z-1)
6. Show that when 0 < |-1|< 2, (z-1)(z-3) Complex Analysis (z-1)" 2+2 =-36 z−3) ² A=0 2(z-1)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section: Chapter Questions
Problem 23RE
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Question
![6. Show that when 0 <|z-1| < 2,
2
(z-1)(z-3)
Complex Analysis
=-3 (²-=-=-1)²
2n+2
n=0
2(2-1)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6efe5afb-e398-44b6-84dd-762b9c7cf798%2F6e23940a-cb9f-44cd-b72c-d154107aa150%2Frr3vjg7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Show that when 0 <|z-1| < 2,
2
(z-1)(z-3)
Complex Analysis
=-3 (²-=-=-1)²
2n+2
n=0
2(2-1)]
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