6. Show that a constant force field does zero work on a particle that moves once uniformly around the circle x2+y2 Recall that a force field is a function F(x, y) that outputs a vector for each (x, y). To say that the function is constant is to say that it outputs the same vector for every (x, y). = 1. Hint: What does it mean for a force field to be constant?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6. Show that a constant force field does zero work on a particle that moves once uniformly around the circle \(x^2 + y^2 = 1\). Hint: What does it mean for a force field to be constant? Recall that a force field is a function \(F(x, y)\) that outputs a vector for each \((x, y)\). To say that the function is constant is to say that it outputs the same vector for every \((x, y)\).
Transcribed Image Text:6. Show that a constant force field does zero work on a particle that moves once uniformly around the circle \(x^2 + y^2 = 1\). Hint: What does it mean for a force field to be constant? Recall that a force field is a function \(F(x, y)\) that outputs a vector for each \((x, y)\). To say that the function is constant is to say that it outputs the same vector for every \((x, y)\).
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