6. Select the lightest W section of A36 steel to serve as a pinned-end main member column 16 ft long to carry an axial compression load of 95 kips dead load and 100 kips live load in a braced structure as shown in Figure +² Hinged www A36 steel Hinged 77117 te 16-0

6. Select the lightest W section of A36 steel to serve as a pinned-end main member column 16 ft long to carry an axial compression load of 95 kips dead load and 100 kips live load in a braced structure as shown in Figure +² Hinged www A36 steel Hinged 77117 te 16-0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: By using LRFD method determine the max load (P) can be applied on the structure shown to be tension…

Q: A W14 X 82 of 50 ksi steel is to be investigated for use as a beam-column in an unbraced frame. The…

A: Section- W14×82L= 14 ftPe story=40,000 kipsPstory=6000 kipsKx=1 (non sway)Kx=1.7 (sway)Ky=1

Q: Refer to Fig-III Design Shear reinforcement for the beam shown in figure. fyt =300Mpa. Main steel is…

Q: snip

A: Effestive slinderness ratioλ=KLrXorKLrYmaxWhere K-length ratio , L - length of the member and r=…

Q: A simply supported beam with a span length of 48 feet is laterally supported at its ends and is…

A: Span of simply supported beam = 45 ftDead load = 400 lb/ftLive load = 1000 lb/ftSection of the beam…

Q: 8. A W12 × 65 of A572 Grade 60 (414 Mpa) steel is used as a compression member. It is 7.9m long,…

A: Given, W12 x 65 Fy = 414 MPa DL = 600 kN LL = 1420 kN

Q: 1. Determine the buckling strength of column C1 shown below and check the inelastic column buckling…

A: Given data: Steel A572 grade 345 material Fy=50 ksi Section for column C1, W460x177 Ag=22600 mm2…

Q: W8x40 sections are used as columns in a braced frame with W16x26 beams at the top and the bottom of…

A: To determine the effective length using the alignment chart for the strong axis, we need to consider…

Q: H.W -4: For the beam of sections and detail shown in Fig. find the maximum live load (PL) that the…

A: at section a-a b = 350 mmh = 600 mmfc' = 35 MPafy = 420 MPaArea of steel at bottom = 5- dia 25…

Q: Xz Select the lightest W section of A36 steel to serve as a main member 30 ft long to carry an axial…

Q: se Allowable Strength Design. Use A992 steel and select a W-shape for the following beam: •…

A: Given- Service dead load = 0.4 kips/ftService live load = 1.2 kips/ftdead load=10kiplive load=12…

Q: Sidesway is prevented for the beam-column shown in the Fig. P11-17. If the first-order momen ts…

A: LRFD is another steel building design tool. It allows the designer to choose the design methodology.…

Q: An I-section shown in Fig. is simply supported over a span of 12 m. If the maximum permissible…

Q: PROBLEM 8 USING THE METHOD OF JOINTS, DETERMINE THE FORCE IN EACH MEMBER OF 4 ft 3000 Ib 1000 Ib THE…

Q: The beam under the Live and Dead loads is shown below. The steel class is $235. 9.% L1 L2- a.)…

A: Step-1

Q: Find solution steel structure

A: The image you sent is a part of a (civil engineering) design problem. The text specifies a member AB…

Q: Problem #3: The frame shown in Fig. 3 is subjected to a live load of P. The beam abcd is made with…

Q: Situation 3: A W12x22 simply supported beam carries a uniformly distributed load. The properties of…

Q: solve force in members DE, EK, and KJ

A: ASKED: To determine the force in members DE, EK and KJ.

Q: 1. Draw the FBDs of the required rigid frame. (a) (b) в а (c) A W q B B DC B M C с

Q: TENI Q P 160 KN Beam S Hinge 2m 2 m- R

A: Given. Load = 160 kN PQ = 2 m QR = 4 m

Q: The truss shown is composed of steel sections. If the 2L150 x 90 x 8 A36 steel section was used in…

Q: NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to…

A: Net power output =280 MW. Pressure ratio of the gas turbine cycle =11 Air enters the compressor at…

Q: Determine the end moments that can safely be carried by a UC 254 x 254 x 107 in S355 steel, assuming…

A: The objective of the question is to determine the end moments that can safely be carried by a UC 254…

Q: 1. Design the most economical A36 steel base plate to resist a dead load = 1,400 kN and a live load…

A: Solving the first problem: Given: Live Load = 1700 kN; Dead Load = 1400 kN fc = 27 MPa; Column…

Q: A L1 B P1 L1 The steel beam ABC has a central point load P1 = 40 kN acting at a distance L1 = 2.8…

A: Given S355 Grade Universal beam is used.

Q: A W21 x 68 of A992 steel is used as a simply supported beam with a span length of 50 feet. The only…

A: For section ,

Q: For the beam(300x800mm) to carried the loads shown in the figure below,design the steel…

A: Given values: Size of beam: (Width b * Depth D) = 300 * 800 mm Span = 9 m f'c = 25 MPa fy = 414 MPa…

Q: A WT205 × 30 structural steel section (see Appendix B for cross-sectional properties) is used for a…

A: To Find a. Slenderness ratio b. Euler buckling load c. Axial stress in column Given data WT205×30…

Q: Design the most economical member for truss member L1 of the truss shown below. It is to consist of…

Q: A compression member is built up from a W14x90 and a W10x49, both of A992 steel. a. Compute rx and…

A: We need to first obtain the Moment of inertia about X and Y axis We can determine the moment of…

Q: 04) Design the braced column shown in Fig. (4) if it has an unsupported length of 6.5 m. Analysis…

A: Step 1:First, we need to figure out which LFRD rule to use, kind of like picking the right…

Q: A 12 ft D B 12 ft F 10 k E C 5k 10 k 16 ft 16 ft

Q: ully welded together. The PL16×380 and PL12X500 for the

A: the flexural strength is given by F =PLbd2where . p = load on beam L = length b =…

Q: 1,115 kN 325 kN.m Determine whether the given member satisfies the appropriate NSCP interaction…

Q: AW14 x 53 of Grade 70 steel is used as a compression member. It is 30 feet long, pinned at the top…

Q: An 80-foot long plate girder (see below) is fabricated from a ½-inch x 78-inch web and two 3inch x…

A: Dead Load Live Load Concentrated Live Load Girder Length Flanges: Two Web: Steel Material:…

Q: For the beam shown Pind IL. Por RA dueto uniferm load (skNim) and concentrated load (lokn) only…

A: Given data Internal hinge UDL Point load I will draw ILD using Muller Breslau Principle.

Q: Verify the adequacy of column AB, part of a sway frame structure, to carry the loads shown in the…

A: fy = 250MPa

Q: Current Attempt in Progress A pin-connected structure is supported and loaded as shown. Member ABCD…

A: Given data -

Q: A simply supported beam with a span length of 48 feet is laterally supported at its ends and s…

A: Span of simply supported beam = 45 ftDead load = 400 lb/ftLive load = 1000 lb/ftSection of the beam…

Q: Find solution steel structure

A: The text in the image asks you to design member AB within the frame shown in figure (2). The applied…

Q: 6.9-2 Use A992 steel and select a structural tee shape for the top chord of the truss shown in…

Q: In a truss girder of a bridge, a diagonal consists of mild steel flat 400 ISF and carries a pull of…

Q: Reinforce an existing simply supported W16x36 beam made of A36 steel to carry a service dead load of…

Concept explainers

Steel Framing

A steel frame consists of a skeleton frame structure comprising of horizontal I-beams and vertical steel columns fitted in a rectangular grid building construction to brace the floors, walls, and the roof of the building held onto the frame. Due to the implementation of this methodology, the construction of the skyscrapers was feasible.

Question

6. Select the lightest W section of A36 steel to serve as a pinned-end main
member column 16 ft long to carry an axial compression load of 95 kips dead
load and 100 kips live load in a braced structure as shown in Figure
+²
Hinged www
A36
steel
Hinged
77117
te
16-0

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given details

VIEW

Step 2: Required gross area (Ag)

VIEW

Step 3: Euler's buckling stress of W16x31

VIEW

Step 4: Axial compressive strength of W16x31

VIEW

Step 5: Euler's buckling stress of W18x50

VIEW

Step 6: Axial compressive strength of W18x50

VIEW

Solution

VIEW

Step by step

Solved in 7 steps with 7 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

W 14 x 142 is used as a column having a length of 9 m. long. It is hinged at the r end and fixed at the lower end but there is a lateral bracing perpendicular to minor axis of the W section at a point 6 m. above the bottom support. It is assumed to be pinned connected at the bracing point. Using A 36 steel Fy 248 MPa the NSCP Specifications. E= 200000 MPa. Properties of W 14 x 142 A-26967.69 mm2 d=374.65 mm bf=393.70 mm tf-27.00 mm tw 17.27 mm Ix 695.11 x 106 mm4 Iy = 274.71 x 106 mm4 rx = 160.53 mm ry 100.84 mm 221 Assume: Kx=0.80 for 9 m. length KY 1.9 for the length on the upper support KY-0.80 for the length on the bottom support CIVIL ENGINEERING- STEEL DENON a) Compute the slenderness ratio along y-axis. b) Compute the slenderness ratio along x-axis. c) Compute the safe axial load
4.7-2 An HSS 10 x 6 x 6 with F 46 ksi is used as a column. The length is 15 feet. Both ends are pinned, and there is support against weak axis buckling at a point 6 feet from the top. Determine a. the design strength for LRFD. b. the allowable stress for ASD.
Analysis of frames/Zero force identification please show complete solution
4
The rigid frame shown in Figure is unbraced in the plane of the frame. In the direction perpendicular to the frame, the frame is braced at the joints. The connections at these points of bracing are simple (moment-free) connections. Roof girders are W14 x 30, and floor girders are W16 x 36. Member BC is a W10 x 45. Use A992 steel and select a W-shape for AB. Assume that the controlling load combination causes no moment in AB. The service dead load is 25 kips and the service live load is 75 kips. a. Use LRFD. b. Use ASD
The floor structural system shown in Fig 1 comprise W-section steel beams and girders supporting a 5-inch thick concrete slab which provides full restraint to the flanges of the beams. The density of concrete is 150 lbs./ft'. and the uniformly distributed live load L- 50 lbs/ft². L-22 B. Girder G1: - B [za] 12' GI GI 12 + [ial FIG. 1-Steel Floor Beam a) Strength - Bending and Shear -I 1) Produce a sketch of the floor plan showing the tributary load distribution areas for the beams and girders [za]
Design the member A-B to withstand the given loads P3 =12, W1=14 KN/m, P1 = 20 KN, P2 = 20 KN L = 7m, H1 = 4m H2 = 6m, P1 at L/3, P2 at 2L/3 notes choose proper material, all loads are unfactored Dead loads assume K= 0.7 P3 H2 A B HINGE W1 D P1 P2 H1 L HINGE C
A bracket of length 1.5m is rigidly attached to the simply-supported beam at its end. The beam is subjected to the combined effect of M,, M, and compressive force P caused by the factored loads as shown. There are lateral supports only at the ends. The member is made of HE300A section and steel grade is S275 (Fy-275MPA, Fu= 430 MPa). The loads acting are determined from LRFD combinations. Determine whether the member can safely carry the applied loads. Multiply first-order moment diagrams by a factor of 1.2 to account for second-order effects. No need to check shear limit state. You do not need to additionally consider the beam self-weight. E Use the following simple expression to calculate the value of L:: L, = T*rts 0.7*Fy y P = 400kN 1.5 m F = 150kN 2 т 4 т X: Lateral support НЕЗ00А
Use A992 steel and select a W14 shape for an axially loaded column to meet the following specifications: The length is 22 feet, both ends are pinned, and there is bracing in the weak direction at a point 10 feet from the top. The service dead load is 142 kips, and the service live load is 356 kips. a. Use LRFD. b. Use ASD.
steel structure (AISC ) masnual
Determine if the members AL, AB, FG, FH, and BL are under zero-force membercompressed membertensile membernot a member
The floor structural system shown in Fig 1 comprise W-section steel beams and girders supporting a 5-inch thick concrete slab which provides full restraint to the flanges of the beams. The density of concrete is 150 lbs. /ft³. and the uniformly distributed live load L=50 lbs/ft². L-22¹ B B. Girder G1: - [82] 12' Gl GI [BI] FIG. 1-Steel Floor Beam a) Strength - Bending and Shear 12' + I 1) Produce a sketch of the floor plan showing the tributary load distribution areas for the beams and girders [zul