6. S x³ √9+ x² dx x = 3 tan 0

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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5-8 Evaluate the integral using the indicated trigonometric
substitution. Sketch and label the associated right triangle.
6. S
x³
/9 + x²
dx
x = 3 tan 0
9-36 Evaluate the integral.
14. S
dt
1²√1² - 16
Transcribed Image Text:5-8 Evaluate the integral using the indicated trigonometric substitution. Sketch and label the associated right triangle. 6. S x³ /9 + x² dx x = 3 tan 0 9-36 Evaluate the integral. 14. S dt 1²√1² - 16
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