6. Place the metal solutions you tested in order of increasing energy based on the colors observed in the flame test; i.e., A < В < С.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6. Place the metal solutions you tested in order of increasing energy based on the colors observed in the flame test; i.e., A <
В « С.
Normal
BII|U
X2| X² |
三1
fx| | D e
田=|T||二
Transcribed Image Text:6. Place the metal solutions you tested in order of increasing energy based on the colors observed in the flame test; i.e., A < В « С. Normal BII|U X2| X² | 三1 fx| | D e 田=|T||二
Activated
LiCI
NaCl
KCI
CaCl2
SrCl, charcoal*
Transcribed Image Text:Activated LiCI NaCl KCI CaCl2 SrCl, charcoal*
Expert Solution
Step 1

When a certain metals or a elements are placed in the flame, the electrons of the atom get excited by absorbing the heat energy  from the flame. When the electrons return back from the excited state to lower energy level, the absorbed energy is released in the form of photon having certain wavelength and energy. This emitted photon may have wavelength in the visible range or in the UV or radiation as well. The color observed in the flame is a combination of different wavelengths.

Now, the relation between the wavelength and the energy of the emitted photons is inversely proportional. As the wavelength is higher, energy emitted will by the photon will be lower. This is given by the equation as follows.

E=h·cλ

E is the energy of the photon.

h is the Planck's constant

c is the speed of the light

λ is the wavelength of photon.   

 

   

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