6. (McQuarrie 5-26) Show that (x²) = [*° 42(x)*x²+2(x)dx = 5 h = 2 √μk for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of the oscillator. 7. (McQuarrie 5-27) Show that (p) = 0 and {p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk for a harmonic oscillator.
6. (McQuarrie 5-26) Show that (x²) = [*° 42(x)*x²+2(x)dx = 5 h = 2 √μk for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of the oscillator. 7. (McQuarrie 5-27) Show that (p) = 0 and {p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk for a harmonic oscillator.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:6. (McQuarrie 5-26) Show that
(x²) = [*° 42(x)*x²+2(x)dx =
5 h
=
2 √μk
for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of
the oscillator.
7. (McQuarrie 5-27) Show that (p) = 0 and
{p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk
for a harmonic oscillator.
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