6. (McQuarrie 5-26) Show that (x²) = [*° 42(x)*x²+2(x)dx = 5 h = 2 √μk for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of the oscillator. 7. (McQuarrie 5-27) Show that (p) = 0 and {p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk for a harmonic oscillator.
6. (McQuarrie 5-26) Show that (x²) = [*° 42(x)*x²+2(x)dx = 5 h = 2 √μk for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of the oscillator. 7. (McQuarrie 5-27) Show that (p) = 0 and {p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk for a harmonic oscillator.
Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter18: Raman Spectroscopy
Section: Chapter Questions
Problem 18.5QAP
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Please answer both questions!!
![6. (McQuarrie 5-26) Show that
(x²) = [*° 42(x)*x²+2(x)dx =
5 h
=
2 √μk
for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of
the oscillator.
7. (McQuarrie 5-27) Show that (p) = 0 and
{p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk
for a harmonic oscillator.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d378848-bcd2-4fca-91fb-9e70c50f07a7%2F9ae36834-48ef-4205-a01c-8f07c1ae7a82%2Fekf3wd_processed.png&w=3840&q=75)
Transcribed Image Text:6. (McQuarrie 5-26) Show that
(x²) = [*° 42(x)*x²+2(x)dx =
5 h
=
2 √μk
for a harmonic oscillator. The square root of (x²) is the root-mean-square-displacement of
the oscillator.
7. (McQuarrie 5-27) Show that (p) = 0 and
{p²) = [ ¢2(x)*P²v2(x)dx = {2ħ√/µk
for a harmonic oscillator.
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