6. Locate the center of mass, COM, on the bodies below then label all of the forces acting on the body in these two positions. Note: the force of gravity will be directed straight down and is located at the center of mass. Rotating clockwise (unstable) Tha Not Rotating (stable) Torque, t, is a "rotational" quantity defined by a simple equation t = Fxd, where both F and d must be perpendicular to each other. Sometimes it is advantageous to find the force component that is perpendicular to d (the distance to the pivot point). Other times it is easier to leave the force and find the perpendicular distance instead. On the diagram above extend each force of gravity vector so that it reaches the floor. The "pivot" will be the toes. The perpendicular distance will be the distance along the floor between the toes and the extended force of gravity. Label these distances on the diagram. Using these labels, explain why the person on the left rotates clockwise while the person on the right experiences no rotation (you may have to adjust your center of mass position).

6. Locate the center of mass, COM, on the bodies below then label all of the forces acting on the body in these two positions. Note: the force of gravity will be directed straight down and is located at the center of mass. Rotating clockwise (unstable) Tha Not Rotating (stable) Torque, t, is a "rotational" quantity defined by a simple equation t = Fxd, where both F and d must be perpendicular to each other. Sometimes it is advantageous to find the force component that is perpendicular to d (the distance to the pivot point). Other times it is easier to leave the force and find the perpendicular distance instead. On the diagram above extend each force of gravity vector so that it reaches the floor. The "pivot" will be the toes. The perpendicular distance will be the distance along the floor between the toes and the extended force of gravity. Label these distances on the diagram. Using these labels, explain why the person on the left rotates clockwise while the person on the right experiences no rotation (you may have to adjust your center of mass position).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

6. Locate the center of mass, COM, on the bodies below then label all of the forces acting on the body in
these two positions. Note: the force of gravity will be directed straight down and is located at the center
of mass.
Rotating clockwise (unstable)
Torque, t, is a "rotational" quantity defined by a simple equation t = Fxd, where both F and d must be
perpendicular to each other. Sometimes it is advantageous to find the force component that is
perpendicular to d (the distance to the pivot point). Other times it is easier to leave the force and find the
perpendicular distance instead.
Not Rotating (stable)
On the diagram above extend each force of gravity vector so that it reaches the floor. The "pivot" will
be the toes. The perpendicular distance will be the distance along the floor between the toes and the
extended force of gravity. Label these distances on the diagram.
Using these labels, explain why the person on the left rotates clockwise while the person on the right
experiences no rotation (you may have to adjust your center of mass position).
2022-06-10
Page 5 of 12

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