6. int i,sum=0; for (i=10 ; i>0 ; i++){ sum+=i*i; i++; printf("%d\n", sum); 7. int a[3] [3]={{1, 2, 3}, {4, 5, 6}, {7, 8 ,9}}; for (i=0 ; i<3 ; i++){ for (j=0 ; j<3 ; j++){ printf ("%d ",a[j] [i]); } printf("\n"); } 8. int i=10,j=1; while( (i>0) && (j<5) ){ printf ("%d\n",i/j); i--; j++;
6. int i,sum=0; for (i=10 ; i>0 ; i++){ sum+=i*i; i++; printf("%d\n", sum); 7. int a[3] [3]={{1, 2, 3}, {4, 5, 6}, {7, 8 ,9}}; for (i=0 ; i<3 ; i++){ for (j=0 ; j<3 ; j++){ printf ("%d ",a[j] [i]); } printf("\n"); } 8. int i=10,j=1; while( (i>0) && (j<5) ){ printf ("%d\n",i/j); i--; j++;
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
Write down the output on the screen, when the following fragments of code are
executed:
![6. int i,sum=0;
for (i=10 ; i>0 ; i++){
sum+=i*i;
i++;
}
printf("%d\n", sum);
7. int a[3] [3]={{1, 2, 3}, {4, 5, 6}, {7, 8 ,9}};
for (i=0 ; i<3 ; i++){
for (j=0 ; j<3 ; j++){
printf ("%d ", a[j] [i]);
}
printf("\n");
}
8. int i=10,j=1;
while( (i>0) && (j<5) ){
printf("%d\n",i/j);
i--;
j++;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F742deb7a-cb31-44d8-893a-f4cbdfd4cc0d%2F3f7b297b-d6c3-4c90-bf7c-5d8ca169424c%2Fv850p9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. int i,sum=0;
for (i=10 ; i>0 ; i++){
sum+=i*i;
i++;
}
printf("%d\n", sum);
7. int a[3] [3]={{1, 2, 3}, {4, 5, 6}, {7, 8 ,9}};
for (i=0 ; i<3 ; i++){
for (j=0 ; j<3 ; j++){
printf ("%d ", a[j] [i]);
}
printf("\n");
}
8. int i=10,j=1;
while( (i>0) && (j<5) ){
printf("%d\n",i/j);
i--;
j++;
}
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