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6. In a CD player, the sampling rate is 44.1 kHz, and the samples are quantized using a 16 bit/sample quantizer. Determine the resulting number of bits for a piece of music with a duration of 50 minutes.e

6. In a CD player, the sampling rate is 44.1 kHz, and the samples are quantized using a 16 bit/sample quantizer. Determine the resulting number of bits for a piece of music with a duration of 50 minutes.e

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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6. In a CD player, the sampling rate is 44.1 kHz, and the samples are quantized using a 16 bit/sample quantizer. Determine the resulting number of bits for a piece of music with a duration of 50 minutes. Answer: The sampling rate is fs = 44100 meaning that we take 44100 samples per second. Each sample is quantized using 16 bits so the total number of bits per second is 44100 x 16. For a music piece of duration 50 min = 3000 sec the resulting number of bits per channel (left and right) is 44100 x 16 x 3000 = 2.1168 ×x 10^9 and the overall number of bits ise 2.1168 x 10^9 × 2= 4.2336 × 10^9
Transcribed Image Text:6. In a CD player, the sampling rate is 44.1 kHz, and the samples are quantized using a 16 bit/sample quantizer. Determine the resulting number of bits for a piece of music with a duration of 50 minutes. Answer: The sampling rate is fs = 44100 meaning that we take 44100 samples per second. Each sample is quantized using 16 bits so the total number of bits per second is 44100 x 16. For a music piece of duration 50 min = 3000 sec the resulting number of bits per channel (left and right) is 44100 x 16 x 3000 = 2.1168 ×x 10^9 and the overall number of bits ise 2.1168 x 10^9 × 2= 4.2336 × 10^9
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