6. IF 10b16= (0*1s)+(1*16s) = 16 b16, which are the correct next hexadecimal for decimals sequence 32,33 and 34. using incremental counting in 1s place value and observing positioning of hexadecimals. place values. Note: the "s" has been remove to save space. * 20b16 (1*1s)+(2*16s)=32; 21b16=(2*1s)+(2*16s)=33; 22b16= (3*2s)+(1*16s)=34 20b16 = (0*1s)+(2*16s)=32; 21b16=(1*1s)+(2*16s)=33; 22b16= (2*1s)+(2*16s)=34 20b16 = (0*1s)+(2*16s)=32; 21b16=(2*1s)+(2*16s)=33; 22b16= (2*1s)+(2*16s)=34 20b16 (1*1s)+(2*16s)=32; 21b16=(2*1s)+(2*16s)=33; 22b16= (2*2s)+(2*16s)=34 ONITS =

6. IF 10b16= (01s)+(116s) = 16 b16, which are the correct next hexadecimal for decimals sequence 32,33 and 34. using incremental counting in 1s place value and observing positioning of hexadecimals. place values. Note: the "s" has been remove to save space. * 20b16 (11s)+(216s)=32; 21b16=(21s)+(216s)=33; 22b16= (32s)+(116s)=34 20b16 = (01s)+(216s)=32; 21b16=(11s)+(216s)=33; 22b16= (21s)+(216s)=34 20b16 = (01s)+(216s)=32; 21b16=(21s)+(216s)=33; 22b16= (21s)+(216s)=34 20b16 (11s)+(216s)=32; 21b16=(21s)+(216s)=33; 22b16= (22s)+(216s)=34 ONITS =

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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