6. If 0.05 kg of ice at 0°C is added to 2.40 kg of water at 26 °C in a 0.11-kilogram aluminum calorimeter cup, what is the final temperature of the water? (cice = 2000 J/(kg.°C), cw = 4186 J/(kg.°C), L=3.35 x10° J/kg, L,=2.26 ×10° J/kg, cA1 = 900 J/(kg.°C) ) °C

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**Problem 6:** If 0.05 kg of ice at 0°C is added to 2.40 kg of water at 26°C in a 0.11-kilogram aluminum calorimeter cup, what is the final temperature of the water?

Given:
- Specific heat capacity of ice, \( c_{\text{ice}} = 2000 \, \text{J/(kg} \cdot \text{°C)} \)
- Specific heat capacity of water, \( c_{\text{w}} = 4186 \, \text{J/(kg} \cdot \text{°C)} \)
- Latent heat of fusion, \( L_{\text{f}} = 3.35 \times 10^5 \, \text{J/kg} \)
- Latent heat of vaporization, \( L_{\text{v}} = 2.26 \times 10^6 \, \text{J/kg} \)
- Specific heat capacity of aluminum, \( c_{\text{Al}} = 900 \, \text{J/(kg} \cdot \text{°C)} \)

Find the final temperature of the water in °C.

\[ \text{Final Temperature:} \, \, \boxed{\phantom{100}} \, \text{°C} \]
Transcribed Image Text:**Problem 6:** If 0.05 kg of ice at 0°C is added to 2.40 kg of water at 26°C in a 0.11-kilogram aluminum calorimeter cup, what is the final temperature of the water? Given: - Specific heat capacity of ice, \( c_{\text{ice}} = 2000 \, \text{J/(kg} \cdot \text{°C)} \) - Specific heat capacity of water, \( c_{\text{w}} = 4186 \, \text{J/(kg} \cdot \text{°C)} \) - Latent heat of fusion, \( L_{\text{f}} = 3.35 \times 10^5 \, \text{J/kg} \) - Latent heat of vaporization, \( L_{\text{v}} = 2.26 \times 10^6 \, \text{J/kg} \) - Specific heat capacity of aluminum, \( c_{\text{Al}} = 900 \, \text{J/(kg} \cdot \text{°C)} \) Find the final temperature of the water in °C. \[ \text{Final Temperature:} \, \, \boxed{\phantom{100}} \, \text{°C} \]
Expert Solution
Step 1

According to the conservation of energy,

The total heat of the system remain conserved.

The heat gained by the ice should be equal to the heat lost by the water and the aluminum calorimeter.

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