Chapter8: Capacitance
Section: Chapter Questions
Problem 64AP: A capacitor is made from two flat parallel plates placed 0.40 mm apart. When a charge of 0.020C is...
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please type your solution so that it is easy for to read I have bad eyesight pleae and thank you
![### Problem 6
**Question**: How strong is the electric field between two parallel plates 6.8 mm apart if the potential difference between them is 220 V?
### Explanation
To find the strength of the electric field (E) between two parallel plates, we can use the formula:
\[ E = \frac{V}{d} \]
where:
- \( E \) is the electric field strength (measured in volts per meter, V/m),
- \( V \) is the potential difference between the plates (measured in volts, V),
- \( d \) is the separation between the plates (measured in meters, m).
Given:
- \( V = 220 \) V
- \( d = 6.8 \) mm = \( 6.8 \times 10^{-3} \) m
Substitute the given values into the formula:
\[ E = \frac{220 \text{ V}}{6.8 \times 10^{-3} \text{ m}} \]
Calculate the result:
\[ E = \frac{220}{0.0068} \text{ V/m} \]
\[ E \approx 32,353 \text{ V/m} \]
So, the strength of the electric field between the plates is approximately 32,353 volts per meter (V/m).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa96c07fd-e70d-478a-a514-a2ec6704d773%2F81b8cb2e-9d7e-4b34-bd2d-b188f22096d4%2Flng16hq_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem 6
**Question**: How strong is the electric field between two parallel plates 6.8 mm apart if the potential difference between them is 220 V?
### Explanation
To find the strength of the electric field (E) between two parallel plates, we can use the formula:
\[ E = \frac{V}{d} \]
where:
- \( E \) is the electric field strength (measured in volts per meter, V/m),
- \( V \) is the potential difference between the plates (measured in volts, V),
- \( d \) is the separation between the plates (measured in meters, m).
Given:
- \( V = 220 \) V
- \( d = 6.8 \) mm = \( 6.8 \times 10^{-3} \) m
Substitute the given values into the formula:
\[ E = \frac{220 \text{ V}}{6.8 \times 10^{-3} \text{ m}} \]
Calculate the result:
\[ E = \frac{220}{0.0068} \text{ V/m} \]
\[ E \approx 32,353 \text{ V/m} \]
So, the strength of the electric field between the plates is approximately 32,353 volts per meter (V/m).
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