6. Given the following ANOVA table for five treatments each with six observations: Source Sum of Squares df Mean square Treatment 1176 Error 1008 Total 2184 What is the decision regarding the null hypothesis at the 5% significance level? A) Reject Hothere is a difference in treatment means. B) Fail to reject Ho-there is a difference in treatment means. C) Reject Ho-there is a difference in errors. D) Fail to reject Ho-there is a difference in errors.

6. Given the following ANOVA table for five treatments each with six observations: Source Sum of Squares df Mean square Treatment 1176 Error 1008 Total 2184 What is the decision regarding the null hypothesis at the 5% significance level? A) Reject Hothere is a difference in treatment means. B) Fail to reject Ho-there is a difference in treatment means. C) Reject Ho-there is a difference in errors. D) Fail to reject Ho-there is a difference in errors.

Name: 6. Given the following ANOVA table for five treatments each withsix o
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: 6. Given the following ANOVA table for five treatments each withsix observations:SourceSum of SquaresdfMean squareTreatment1176Error1008Total2184What is the decision regarding the null hypothesis at the 5% significance level?A) Reject Ho-there is a

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A researcher is interested in investigating whether religious affiliation and the brand of sneakers that people wear are associated. The table below shows the results of a survey. Frequencies of Religions and Sneakers Nike Adidas Other Protestant 97 87 117 Catholic 68 50 80 Jewish 18 19 38 Other 64 83 70 What can be concluded at the αα = 0.05 significance level? The test-statistic for this data = (Please show your answer to three decimal places.) The p-value for this sample = (Please show your answer to four decimal places.) The p-value is Select an answer less than (or equal to) greater than αα Based on this, we should reject the null fail to reject the null accept the null Thus, the final conclusion is... There is sufficient evidence to conclude that sneaker brand and religious affiliation are dependent. There is insufficient evidence to conclude that the distribution of sneaker brand is not the same for each religion. There is insufficient evidence to…
6) A researcher is interested in whether women like Justin Bieber's music more than men. The extent to which people liked Bieber's music was measured on a 10 point scale ranging from 1 = do not like at all, to 10 like Justin Bieber's music more than men (alpha = .05). very much like. Using the data below, please determine whether women Women Men 7 4 8 7 4 a) What type statistical analysis should you perform? Please explain your rationale b) Please state the null and alternative hypotheses c) Please write out the results (t-value, df, p-value) and make a decision d) Please make a general conclusion (no stats talk)
What is the observed value? What is the p-value? What is the rejection region?
A Gallup Poll of 800 adults showed that 510 adults are opposed to high school students attending school year-round without the traditional summer break. We want to test that more than 60% of all adults oppose year-round school. Use a significance level of a = 0.05. Check all of the conditions that are needed for this test. O 10% Condition O Normality Assumption O Independence Assumption Randomization Condition Success / Failure Condition O Dependence Assumption O Sample Size Assumption
The degrees of freedom for the critical value of a one-way ANOVA obtained from 5 samples, where each sample contains 9 observations is: a. 5 numerator and 9 denominator degrees of freedom. b. 4 numerator and 8 denominator degrees of freedom. c. 45 degrees of freedom. d. 4 numerator and 40 denominator. e. None of the above.
Which statistical method can be considered as an extension of One-Way ANOVA to incorporate a "covariate"? a. two way ANOVA b. ANCOVA c. Normality Testing d. Covariance
Compute a one-way ANOVA on the following data using 0.05 significance level. Group A Group B Group C 14 11 14 13 12 12 10 13 13 12 13 12 14 ANOVA Source of Variation SS df MS F P-value F crit Between Groups ? ? ? ? ? Within Groups ? ? ? Total ? ?
What is the primary purpose of conducting post hoc tests following an ANOVA? a. To determine the overall effect size of the ANOVA. ○ b. To confirm that there are no significant differences among the group means. c. To identify which specific pairs of group means are significantly different from each other. ○ d. To establish a new significance level for the ANOVA.
What is the value of the standard score for the sample proportion?
I chose option 1. I believe that the population mean number of times that adults eat fruit with their breakfast is greater than 3 times. I spoke with 14 adults and found that they had fruit with breakfast 7,2,3,0,0,0,4,7,7,7,4,4,5,and 0 times in the past week. Test this hypothesis at the .05 significance level and assume a random sample.
ARE THE FOLLOWING DATA EQUALLY DISTRIBUTED ACROSS CATEGORIES? TEST AT.05 SIGNIFICANCE LEVEL. ABICID 35 15 10 45 WHAT STATISTICAL TEST WAS USED? OBSERVED VALUE ? CRITICAL VALUE? ACCEPT OR REJECT NULL? DO THE GROUPS DIFFER SIGNIFICANTLY?