6. For the circuit in figure 6. a) Find the value of RL such that Maximum Power is transferred in the circuit. Also find this maximum power- i.e find the value of Rth and Vth b) Find the maximum power R1 R2 4 kn 8 kN 24 V 2i, RL 2 kM b

Q: 6. R=_ kQ 1=4 mA E= 6 V-E P=24 mW

A:

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A:

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A:

Current Division Method

The generalized current divider formula is given by the following relation below,