6. Find the area of the sector below. Show all work! Leave your answer in terms of T. Label your answers with units and simplify the fraction fully. 60° 14 cm

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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### Problem 6: Find the Area of the Sector Below
**Instructions:** Show all work! Leave your answer in terms of π. Label your answers with units and simplify the fraction fully.

#### Given Data:
- Central angle of the sector: 60°
- Radius of the circle: 14 cm

#### Diagram:
The diagram shows a circle with a shaded sector. The sector has a central angle of 60°. The radius of the circle is labeled as 14 cm.

#### Solution:
To find the area of a sector of a circle, use the formula:
\[ A = \pi r^2 \left( \frac{\theta}{360} \right) \]

Where:
- \( A \) is the area of the sector.
- \( r \) is the radius of the circle.
- \( \theta \) is the central angle in degrees.

Substitute the given values into the formula:
- \( r = 14 \) cm
- \( \theta = 60^\circ \)

\[ A = \pi (14)^2 \left( \frac{60}{360} \right) \]
\[ A = \pi (196) \left( \frac{1}{6} \right) \]
\[ A = \pi \left( \frac{196}{6} \right) \]
\[ A = \pi \left( \frac{98}{3} \right) \]

Therefore, the area of the sector is:
\[ \boxed{\frac{98\pi}{3} \text{ cm}^2} \]
Transcribed Image Text:### Problem 6: Find the Area of the Sector Below **Instructions:** Show all work! Leave your answer in terms of π. Label your answers with units and simplify the fraction fully. #### Given Data: - Central angle of the sector: 60° - Radius of the circle: 14 cm #### Diagram: The diagram shows a circle with a shaded sector. The sector has a central angle of 60°. The radius of the circle is labeled as 14 cm. #### Solution: To find the area of a sector of a circle, use the formula: \[ A = \pi r^2 \left( \frac{\theta}{360} \right) \] Where: - \( A \) is the area of the sector. - \( r \) is the radius of the circle. - \( \theta \) is the central angle in degrees. Substitute the given values into the formula: - \( r = 14 \) cm - \( \theta = 60^\circ \) \[ A = \pi (14)^2 \left( \frac{60}{360} \right) \] \[ A = \pi (196) \left( \frac{1}{6} \right) \] \[ A = \pi \left( \frac{196}{6} \right) \] \[ A = \pi \left( \frac{98}{3} \right) \] Therefore, the area of the sector is: \[ \boxed{\frac{98\pi}{3} \text{ cm}^2} \]
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