Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I get the general solution, but am confused why the answer is not e/9(1-e^8)
![The image contains a definite integral expression:
\[
\int_{1}^{9} \frac{e^{9/x}}{x^2} \, dx
\]
This integral is taken from the lower limit of 1 to the upper limit of 9. The function being integrated is \(\frac{e^{9/x}}{x^2}\) with respect to \(x\).
In this expression:
- \(e\) is the base of the natural logarithm.
- The exponent \(9/x\) indicates that \(9\) is divided by \(x\).
- \(x^2\) appears in the denominator, meaning the function involves the square of the variable \(x\).
This type of integral may require techniques such as substitution or integration by parts for evaluation, depending on the context or specific methods being applied.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F29d9ecf2-8ea2-4c7b-b874-691941710284%2F408877c5-c2b3-42d7-a6c2-09a7533eaa77%2Fj332n4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image contains a definite integral expression:
\[
\int_{1}^{9} \frac{e^{9/x}}{x^2} \, dx
\]
This integral is taken from the lower limit of 1 to the upper limit of 9. The function being integrated is \(\frac{e^{9/x}}{x^2}\) with respect to \(x\).
In this expression:
- \(e\) is the base of the natural logarithm.
- The exponent \(9/x\) indicates that \(9\) is divided by \(x\).
- \(x^2\) appears in the denominator, meaning the function involves the square of the variable \(x\).
This type of integral may require techniques such as substitution or integration by parts for evaluation, depending on the context or specific methods being applied.
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