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6. Draw an area model to show that 2/3

6. Draw an area model to show that 2/3

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Instruction:** Draw an area model to show that \(\frac{2}{3} = \frac{6}{9}\). **Explanation:** To illustrate this with an area model, follow these steps: 1. **Start with Two Rectangles:** Each rectangle will represent a whole. 2. **Divide the First Rectangle into Three Equal Parts:** Shade two of these parts to represent \(\frac{2}{3}\). 3. **Divide the Second Rectangle into Nine Equal Parts:** Shade six of these parts to represent \(\frac{6}{9}\). 4. **Compare:** Notice that the shaded area in both rectangles is the same, showing that \(\frac{2}{3}\) is equivalent to \(\frac{6}{9}\). This demonstrates that multiplying the numerator and the denominator of \(\frac{2}{3}\) by 3 does not change its value.
Transcribed Image Text:**Instruction:** Draw an area model to show that \(\frac{2}{3} = \frac{6}{9}\). **Explanation:** To illustrate this with an area model, follow these steps: 1. **Start with Two Rectangles:** Each rectangle will represent a whole. 2. **Divide the First Rectangle into Three Equal Parts:** Shade two of these parts to represent \(\frac{2}{3}\). 3. **Divide the Second Rectangle into Nine Equal Parts:** Shade six of these parts to represent \(\frac{6}{9}\). 4. **Compare:** Notice that the shaded area in both rectangles is the same, showing that \(\frac{2}{3}\) is equivalent to \(\frac{6}{9}\). This demonstrates that multiplying the numerator and the denominator of \(\frac{2}{3}\) by 3 does not change its value.
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