Through the accounts solve the discussion 6. Discussion:1. Is there a difference between the values of the nozzle velocity (vn) andthe jet velocity (v₁)? Why?2. Is there a difference between the values of the water jet force on plate(F₁) when change the plate shape (flat, Conical, and Hemispherical plate)?Why?3. Is there a difference between the values of the water jet force on plate(F₁) and the force exerted by weights on fluid (Fexp)? Why?4. What is the relationship type in the plot between (Fexp) versus (p Qv₁)?Why?5. Is there a difference between the slope from plot and the slope of thevalue (1- Cose)? Why? Calculationtime = 28, Volume = 5, mass: 70, h = 5. __VOL51=0.17 m²/sec(V₁ = = 0.17time2812.56A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh= 0.013-√2016)=83.64FJ=9Q VJ (1-cose)=(1/(0-17) (83.64) (1-C0545)= 4.26590-45, time = 32, Volume = 5, mass=140/V₁=Q = Vol = 5= 0.15 m²/sietim 32..1512.56A=Id=-(6)=12.56² / V5= Vn -√2gh=0.011-√√2x 140.50= 118.3FJ=A@v₂ (1-cosys)=(1)(0.15) (118.3) (0.31= 5.323J0=45= 0.013 mhuh: 50mm= 0.011 m/s.cCalculationD 0=9 time=19, mass: 1oo, ho 50mm, Volume 5Vol 50.26 m²/seetime 19/ VniV₁ = @=0.2612.56A= d² = (16) = 12.56 m² / V5= V₁-√2gh=0.02-√2x100 50= 100FJ=PQV₂ (1-C059)=(1) (0-26) (100) (1-0)= 2690-9:time = 23, mass = 70, h = 50mm, Volum. 5VOL50.21/V₁=== 0.21 m²/91.125623A=Id': (6) = 12.56 m²VS-Vu-Jegh= 0.016-√2+70×5FJ= POV, (1-cosq:)= 83.64=(1) (0.21) 183.64)(1)= 17.56= 0.02 m/sec= 0.016 m/s.

Answered: Image /qna-images/answer/533c03f3-fe2c-4745-b888-cb10e5a6840c.jpg

6. Discussion: 1. Is there a difference between the values of the nozzle velocity (vn) and the jet velocity (vj)? Why? 2. Is there a difference between the values of the water jet force on plate (F₁) when change the plate shape (flat, Conical, and Hemispherical plate)? Why? 3. Is there a difference between the values of the water jet force on plate (F₁) and the force exerted by weights on fluid (Fexp)? Why?

6. Discussion: 1. Is there a difference between the values of the nozzle velocity (vn) and the jet velocity (vj)? Why? 2. Is there a difference between the values of the water jet force on plate (F₁) when change the plate shape (flat, Conical, and Hemispherical plate)? Why? 3. Is there a difference between the values of the water jet force on plate (F₁) and the force exerted by weights on fluid (Fexp)? Why?

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Measuring site work, Excavation and Piling

Bid drawings typically include very little material about the precise requirements of site work operations, measuring site work and excavation work differs from measuring most other works on a construction project. The actual site work conditions are not provided and also the dimensions of the excavations are not known during the pre-construction phase. The precise measurement of the excavation and backfill of the earth material and topsoil is important for a contractor to decide upon the total cost required for the process. All the works should be carried out under OSHA (Occupational Safety and Health Administration) standards to ensure the safety of the workers.

Question

Through the accounts solve the discussion

6. Discussion:
1. Is there a difference between the values of the nozzle velocity (vn) and
the jet velocity (v₁)? Why?
2. Is there a difference between the values of the water jet force on plate
(F₁) when change the plate shape (flat, Conical, and Hemispherical plate)?
Why?
3. Is there a difference between the values of the water jet force on plate
(F₁) and the force exerted by weights on fluid (Fexp)? Why?
4. What is the relationship type in the plot between (Fexp) versus (p Qv₁)?
Why?
5. Is there a difference between the slope from plot and the slope of the
value (1- Cose)? Why?

Calculation
time = 28, Volume = 5, mass: 70, h = 5. __
VOL
5
1=0.17 m²/sec
(V₁ = = 0.17
time
28
12.56
A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh
= 0.013-√2016)
=83.64
FJ=9Q VJ (1-cose)
=(1/(0-17) (83.64) (1-C0545)
= 4.265
90-45, time = 32, Volume = 5, mass=140
/V₁=
Q = Vol = 5= 0.15 m²/sie
tim 32
..15
12.56
A=Id=-(6)=12.56² / V5= Vn -√2gh
=0.011-√√2x 140.50
= 118.3
FJ=A@v₂ (1-cosys)
=(1)(0.15) (118.3) (0.31
= 5.323
J
0=45
= 0.013 mhu
h: 50mm
= 0.011 m/s.c
Calculation
D 0=9 time=19, mass: 1oo, ho 50mm, Volume 5
Vol 50.26 m²/see
time 19
/ Vni
V₁ = @=
0.26
12.56
A= d² = (16) = 12.56 m² / V5= V₁-√2gh
=0.02-√2x100 50
= 100
FJ=PQV₂ (1-C059)
=(1) (0-26) (100) (1-0)
= 26
90-9:
time = 23, mass = 70, h = 50mm, Volum. 5
VOL
5
0.21
/V₁==
= 0.21 m²/91.
1256
23
A=Id': (6) = 12.56 m²
VS-Vu-Jegh
= 0.016-√2+70×5
FJ= POV, (1-cosq:)
= 83.64
=(1) (0.21) 183.64)(1)
= 17.56
= 0.02 m/sec
= 0.016 m/s.

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