6. Diprotic oxalic acid (HO2C−CO2H) ionizes in water as follows. HO2C−CO2H + H2O HO2C−CO2- + H3O+ Ka1= 5.62×10−2 HO2C−CO2- + H2O -O2C−CO2- + H3O+ Ka2 = 5.42× 10−5 You may use the abbreviations H2A, HA- and A2- for HO2C−CO2H, HO2C−CO2- and -O2C−CO2- respectively. 6A. Determine the pH, and the concentrations of [HO2C−CO2H], [HO2C−CO2-] and [-O2C−CO2-] in a solution of 0.100 M aqueous oxalic acid (HO2C−CO2H) solution. Note that Ka1 is not too small compared to the initial concentration (F) of oxalic acid. 6B. Estimate the pH of 0.10 M solution of potassium oxalate (HO2C−CO2- K+): 6C. Complete the following ladder diagram by marking the values of pKa1 and pKa2 and the dominant species resulting from the ionization of oxalic acid (HO2CCO2H) in each pH region to determine the dominant form at pH = 3.80. Only answer 6C
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
HO2C−CO2H + H2O HO2C−CO2- + H3O+ Ka1= 5.62×10−2
HO2C−CO2- + H2O -O2C−CO2- + H3O+ Ka2 = 5.42× 10−5
You may use the abbreviations H2A, HA- and A2- for HO2C−CO2H, HO2C−CO2- and -O2C−CO2-
respectively.
6A. Determine the pH, and the concentrations of [HO2C−CO2H], [HO2C−CO2-] and [-O2C−CO2-] in a
solution of 0.100 M aqueous oxalic acid (HO2C−CO2H) solution. Note that Ka1 is not too small compared to
the initial concentration (F) of oxalic acid.
6B. Estimate the pH of 0.10 M solution of potassium oxalate (HO2C−CO2- K+):
dominant form at pH = 3.80.


Step by step
Solved in 4 steps with 8 images









