6. Determine the focal length in air of a thin spherical plano-convex (radius of curvature is infinite for one side and finite for the other side) lens having a radius of curvature of 50.0mm and an index of 1.5. What, if anything, would happen to the focal length if lens were placed in a tank of water? (Refractive index of water is 4/3)

What is the angular magnification of a telescope that has a 100 cm local length objective and a 2.50 cm focal length eyepiece?

The magnification of an upright image that is 34.0 cm away from its object is 0.400. What type of lens is used to form the image, and what is its focal length?

It has become common to replace the cataractclouded lens of the eye with an internal lens. This intraocular lens can be chosen so that the person has perfect distant vision. Will the person be able to read without glasses? If the person was nearsighted, is the power of the intraocular lens greater or less than the removed lens?

A prism that has an apex angle of 50.0 is made of cubic zirconia. What is its minimum angle of deviation?

(a) Where does an object need to be placed relative to a microscope for its 0.500 cm focal leng1h objective to produce a magnification of 400? (b) Where should the 5.00 cm focal length eyepiece be placed to produce a further fourfold (4.00) magnification?

. (a) In a camera equipped with a 50-mm focal-length lens, the maximum distance that the lens can be from the film is 60 mm. What is the smallest distance an object can be from the camera if its image on the film is to be in focus? What is the magnification? (b) An extension tube is added between the lens and the camera body so that the lens can be positioned 100 mm from film. How close can the object be now? What is the magnification?

The contact-lens prescription for a nearsighted person is —4.00 D and the person has a far point of 22.5 cm. What is the power of the tear layer between the cornea and the lens if the correction is ideal, taking the tear layer into account?

. If the mirror described in the previous problem is used to form an image of the same object now located 16 cm in front of the mirror, what would the new image position be? Assuming that the magnification equations developed for lenses also apply to mirrors, describe the image (size and orientation) thus formed.

A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.