6. Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equation below. 2A1+ 6HCI → 2 AICI3 + 3 H₂ a. b. c. d. e. 1.5 g 2.0 g 3.0 g 6.0 g 12 g 7. How many grams of nitric acid, HNO3, can be prepared from the reaction of 138 g of NO2 with 54.0 g H₂O according to the equation below? 3NO₂ + H₂O → 2HNO3 + NO a. b. C. 92 108 126

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6. Calculate the mass of hydrogen formed when 27 g of
aluminum reacts with excess hydrochloric acid according
to the balanced equation below.
2A1+ 6HCI → 2 AICI3 + 3 H₂
b.
c.
d.
e.
7. How many grams of nitric acid, HNO3, can be prepared
from the reaction of 138 g of NO2 with 54.0 g H₂O
according to the equation below?
3NO₂ + H₂O → 2HNO3 + NO
a.
b.
1.5 g
2.0 g
3.0 g
6.0 g
12 g
C.
d.
e.
92
108
126
189
279
Transcribed Image Text:6. Calculate the mass of hydrogen formed when 27 g of aluminum reacts with excess hydrochloric acid according to the balanced equation below. 2A1+ 6HCI → 2 AICI3 + 3 H₂ b. c. d. e. 7. How many grams of nitric acid, HNO3, can be prepared from the reaction of 138 g of NO2 with 54.0 g H₂O according to the equation below? 3NO₂ + H₂O → 2HNO3 + NO a. b. 1.5 g 2.0 g 3.0 g 6.0 g 12 g C. d. e. 92 108 126 189 279
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