6. Calculate the formation enthalpy (AHform) for benzene (CoHs). Is this reaction endothermic or exothermic?2C,H, + 150, 12CO, + 6H20AH° = -6535 k)AHorm values: O;: 0 kJ/mol - CO;: -393.5 k/mol - H;O: -285.8 kJ/molM = 1 g/mol, Mc = 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K

The enthalpy change of a reaction (∆Hrxn) can be calculated from enthalpy of formations of Products…

6. Calculate the formation enthalpy (AHorm) for benzene (C&Hs). Is this reaction endothermic or exothermic? 2C,H, + 150, 12CO2 + 6H,0 AH° = -6535 k] AHor values: Oz: 0 kJ/mol - CO;: -393.5 kJ/mol - H;O: -285.8 kJ/mol form M = 1 g/mol, Mc = 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K %3D

6. Calculate the formation enthalpy (AHorm) for benzene (C&Hs). Is this reaction endothermic or exothermic? 2C,H, + 150, 12CO2 + 6H,0 AH° = -6535 k] AHor values: Oz: 0 kJ/mol - CO;: -393.5 kJ/mol - H;O: -285.8 kJ/mol form M = 1 g/mol, Mc = 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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6. Calculate the formation enthalpy (AHform) for benzene (C,Hs). Is this reaction endothermic or exothermic? 2C,H6 + 150, 12C02 + 6H20 AH° = -6535 kJ AHPorm values: O;: 0 kJ/mol - CO;: -393.5 kJ/mol - H;O: –285.8 kJ/mol MH = 1 g/mol, Mc = 12 g/mol, Mo = 16 g/mol, R = 0.08206 L.atm/mol.K or 8.314 J/mol.K
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