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6. Balance each skeleton reaction, use Appendix D to calcu- late Ell, and state whether the reaction is spontaneous: (a) Mn²*(aq) + Cơ³*(aq) –→ MnO2(s) + Co²*(aq) [acidic] (b) AgCl(s) + NO(g) → Ag(s) + Cl-(aq) + NO;¯(aq) [acidic] · cell

6. Balance each skeleton reaction, use Appendix D to calcu- late Ell, and state whether the reaction is spontaneous: (a) Mn²*(aq) + Cơ³*(aq) –→ MnO2(s) + Co²*(aq) [acidic] (b) AgCl(s) + NO(g) → Ag(s) + Cl-(aq) + NO;¯(aq) [acidic] · cell

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Galvanic Cell 

Balance each skeleton reaction, use Appendix D to calcu- 6. late Eell, and state whether the reaction is spontaneous: (a) Mn²*(aq) + Co³*(aq) –→ Mn0,(8) + Co²*(aq) [acidic] (b) AgCl(s) + NO(g) → Ag(s) + Cl¯(aq) + N0,¬(aq) [acidic] -
Transcribed Image Text:Balance each skeleton reaction, use Appendix D to calcu- 6. late Eell, and state whether the reaction is spontaneous: (a) Mn²*(aq) + Co³*(aq) –→ Mn0,(8) + Co²*(aq) [acidic] (b) AgCl(s) + NO(g) → Ag(s) + Cl¯(aq) + N0,¬(aq) [acidic] -
Half-Reaction E° (V) F;(g) + 2e= 2F (aq) Os(g) + 2H*(aq) + 2e¯ 0,(g) + H;O(I) Co* (aq) + e= Co*(aq) H,O2(aq) + 2H (aq) + 2e 2H,O() PbO,(s) + 3H*(aq) + HSO, (aq) + 2e PbSO,(8) + 2H;O(I) Ce*(aq) + e=Ce*(aq) MnO, (aq) + 8H*(aq) + Se = Mn²*(aq) + 4H;O(1) Au* (aq) + 3e Au(s) Cl(g) + 2e= 2C1 (aq) Cr;0, (aq) + 14H*(aq) + 6c¯ 20* (aq) + 7H,0(1) MnO,(s) + 4H* (aq) + 2e¯ = Mn*(aq) + 2H;O(1) O:(g) + 4H (aq) + 4e Brz() + 2e 2B1¯(aq) NO, (aq) + 4H* (aq) + 3e NO(g) + 2H,O(1) 2Hg**(aq) + 2e =Hg;²*(aq) Hgz" (aq) + 2e 2Hg() Ag*(aq) + e= Ag(s) Fe" (aq) + e= Fe*(aq) O,(g) + 2H*(aq) + 2e¯ H;0,(aq) MnO, (aq) + 2H;O(1) + 3e¯ MnO(s) + 40H (aq) I(s) + 2e 21 (aq) O,(g) + 2H;0() + 4c¯= 40H"(aq) Cu* (aq) + 2e Cu(s) +2.87 +2.07 +1.82 +1.77 +1.70 +1.61 +1.51 +1.50 +1.36 +1.33 +1.23 = 2H;0(1) +1.23 +1.07 +0.96 +0.92 +0.85 +0.80 +0.77 +0.68 +0.59 +0.53 +0.40 +0.34 Sn** (ag) + 2e = Sn²* (aq) 2H*(aq) + 2e= Hạ(g) Pb?* (aq) + 2e Pb(s) Sn* (aq) + 2e Sn(s) N2(g) + SH*(aq) + 4c¯ N,H,* (aq) Ni (aq) + 2e = Ni(s) Co* (aq) + 2e Co(s) PbSO,(s) + H*(aq) + 2e¯ Pb(s) + HSO,¯(aq) Cd* (aq) + 2e Cd(s) Fe*(aq) + 2e Fe(s) Cr*(aq) + 3e Cr(s) Zn* (aq) + 2e Zn(s) 2H,0(1) + 2e = H2(g) + 20H¯ (aq) C*(ag) + 2e Cr(s) Mn2*(aq) + 2e Mn(s) AlP" (aq) + 3e Al(s) Mg* (aq) + 2e" = Mg(s) Na (aq) + e = Na(s) Ca* (aq) + 2e Ca(s) Sr*(ag) + 2e Sr(s) Ba" (aq) + 2e K*(aq) +e= K(s) Li" (aq) +e 2 Li(s) +0.13 0.00 -0.13 -0.14 -0.23 --0.25 -0.28 -0.31 -0.40 -0.44 -0.74 -0.76 -0.83 -0.91 -1.18 -1.66 -2.37 -2.71 -2.87 -2.89 * Ba(s) -2.90 -2.93 -3.05
Transcribed Image Text:Half-Reaction E° (V) F;(g) + 2e= 2F (aq) Os(g) + 2H*(aq) + 2e¯ 0,(g) + H;O(I) Co* (aq) + e= Co*(aq) H,O2(aq) + 2H (aq) + 2e 2H,O() PbO,(s) + 3H*(aq) + HSO, (aq) + 2e PbSO,(8) + 2H;O(I) Ce*(aq) + e=Ce*(aq) MnO, (aq) + 8H*(aq) + Se = Mn²*(aq) + 4H;O(1) Au* (aq) + 3e Au(s) Cl(g) + 2e= 2C1 (aq) Cr;0, (aq) + 14H*(aq) + 6c¯ 20* (aq) + 7H,0(1) MnO,(s) + 4H* (aq) + 2e¯ = Mn*(aq) + 2H;O(1) O:(g) + 4H (aq) + 4e Brz() + 2e 2B1¯(aq) NO, (aq) + 4H* (aq) + 3e NO(g) + 2H,O(1) 2Hg**(aq) + 2e =Hg;²*(aq) Hgz" (aq) + 2e 2Hg() Ag*(aq) + e= Ag(s) Fe" (aq) + e= Fe*(aq) O,(g) + 2H*(aq) + 2e¯ H;0,(aq) MnO, (aq) + 2H;O(1) + 3e¯ MnO(s) + 40H (aq) I(s) + 2e 21 (aq) O,(g) + 2H;0() + 4c¯= 40H"(aq) Cu* (aq) + 2e Cu(s) +2.87 +2.07 +1.82 +1.77 +1.70 +1.61 +1.51 +1.50 +1.36 +1.33 +1.23 = 2H;0(1) +1.23 +1.07 +0.96 +0.92 +0.85 +0.80 +0.77 +0.68 +0.59 +0.53 +0.40 +0.34 Sn** (ag) + 2e = Sn²* (aq) 2H*(aq) + 2e= Hạ(g) Pb?* (aq) + 2e Pb(s) Sn* (aq) + 2e Sn(s) N2(g) + SH*(aq) + 4c¯ N,H,* (aq) Ni (aq) + 2e = Ni(s) Co* (aq) + 2e Co(s) PbSO,(s) + H*(aq) + 2e¯ Pb(s) + HSO,¯(aq) Cd* (aq) + 2e Cd(s) Fe*(aq) + 2e Fe(s) Cr*(aq) + 3e Cr(s) Zn* (aq) + 2e Zn(s) 2H,0(1) + 2e = H2(g) + 20H¯ (aq) C*(ag) + 2e Cr(s) Mn2*(aq) + 2e Mn(s) AlP" (aq) + 3e Al(s) Mg* (aq) + 2e" = Mg(s) Na (aq) + e = Na(s) Ca* (aq) + 2e Ca(s) Sr*(ag) + 2e Sr(s) Ba" (aq) + 2e K*(aq) +e= K(s) Li" (aq) +e 2 Li(s) +0.13 0.00 -0.13 -0.14 -0.23 --0.25 -0.28 -0.31 -0.40 -0.44 -0.74 -0.76 -0.83 -0.91 -1.18 -1.66 -2.37 -2.71 -2.87 -2.89 * Ba(s) -2.90 -2.93 -3.05
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