6. Assume a Rayleigh-fading environment in which the sensitivity level of an RX is given by asignal amplitude rmin, then the probability of outage is Pout = Pr{r < rmin} = cdf (rmin).(b) The fading margin (level of protection against fading) is expressed asM =(30.5)Cminor (in dB)Мав — Сав — Cmin dB(30.6)%3|dB -Determine a closed-form expression for the required fading margin, in dB, as a functionof outage probability Pout-

Rayleigh fading is a statistical model for the effect of a propagation environment on a radio…

Answered: 6. Assume a Rayleigh-fading environment…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 45 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that o = 7.60 ml/kg for the distribution of blood plasma. (a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) n is large the distribution of weights is normal o is known the distribution of weights is uniform o is unknown (c) Interpret your results in the context of this problem. The probability that this interval contains the true average…
An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated without breaking) for two alloys A and B It is Kknown that the two standard deviations in load capacity are equal at 7 tons each. The experiment is conducted on 50 specimens of each alloy (A and B) and the results are X = 75.8. X = 71.8, and X-X=4. The manufacturers of alloy A are convinced that this evidence shows conclusively that Hug and strongly supports the claim that their alloy is superior. Manufacturers of alloy 8 claim that the experiment could easily have given X-X 4 even if the two population means are equal. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA-XB41 PA-HB) P(XA-X > 4) - @
Question 4 Use the empirical rule to solve the problem. The amount of Jen's monthly phone bill is normally distributed with a mean of $58 and a standard deviation of $12. What percentage of her phonė bills are between $22 and $94? O 99.99% O 99.7% O 68% O 95% « > A Moving to another question will save this response. 4:42 PM rch 3/25/2021 DII FS PrtScn Home F9 End F10 PgUp PgDn F11 F12 F6 F7 F8 4. 5 6 8. 9. E R T Y U D F G H J K L
Answer #3 only, show commplete solution.
The time to first failure X of the software of a medical linear acceleratormay be modeled normal with μ = 1100 hours and σ = 50 hours.
From generation to generation, the mean age when smokers first start to smoke varies. However, the standard deviation of that age remains constant at around 2.1 years. A survey of 38 smokers of this generation was done to see if the mean starting age is at least 19. The sample mean was 18.1 with a sample standard deviation of 1.3. Do the data support the claim at the 5% level? (i) Alpha (Enter an exact number as an integer, fraction, or decimal.)? =
Suppose that X follows a lognormal distribution with w^2=4 and E(X)=10,000 a. Find the parameter theta for the distribution. Use 4 digits after the decimal point: b. Find the standard deviation of the process: Use 4 digits after the decimal point:
A certain variable has a bell-shaped distribution with mean μ=176.16μ=176.16 and standard deviation σ=4.9σ=4.9. You observe a value of x=184x=184. Is this a TYPICAL value of the variable (within 2 standard deviations of the mean), or an UNUSUAL one (more than 2 standard deviations from the mean)?
The probability that an event will not happen is PE′=0.79. Find the probability that the event will happen.

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