6. Acceleration due to gravity and centripetal acceleration of the moon The Moon remains in its orbit around the Earth rather than falling to the Earth because (a) it is outside of the gravitational influence of the Earth; (b) it is in balance with the gravitational forces from the Sun and other planets; (c) the net force on the Moon is zero; (d) none of these; (e) all of these. Earth Moon SBEY Fig.8. 4 As it revolves around the Earth, the Moon experiences a centripetal acceleration a directed toward the Earth. An object near the Earth's surface, such as the apple shown here, experiences an acceleration g.

6. Acceleration due to gravity and centripetal acceleration of the moon The Moon remains in its orbit around the Earth rather than falling to the Earth because (a) it is outside of the gravitational influence of the Earth; (b) it is in balance with the gravitational forces from the Sun and other planets; (c) the net force on the Moon is zero; (d) none of these; (e) all of these. Earth Moon SBEY Fig.8. 4 As it revolves around the Earth, the Moon experiences a centripetal acceleration a directed toward the Earth. An object near the Earth's surface, such as the apple shown here, experiences an acceleration g.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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5. Two asteroids exert a gravitational force, F, on each other. Sometime later, the asteroids are now three times as far from each other as before. Which of the following represents the gravitational force at this distance? F/3 F/2 F/6 F/9
5. When you whirl a ball on a cord in a vertical circle, you find a critical speed at the top for which the tension in the cord is zero. This is because the force of gravity on the object itself supplies the necessary centripetal force. How slowly can you swing a 2.5 kg ball like this so that it will just follow a circle with a radius of 1.5 m?
Exemplary: 7. If the gravitational field strength of earth is 9.81 N/kg at a distance of 1r, by what factor would the force change is the object was 0.5r? What is the force at this distance?
1] Refer to the given figure shows a man spinning a ball on the string. The centripetal force will act on the ball to keep the ball in circular motion. What will happen if the centripetal force is removed? What will be the effect on the motion of the ball? Centripetal force (a) Spinning a ball on a string or twirling a lasso
4. Drag the moon to various locations in order to determine the quantitative effect of distance upon the gravitational force. Examine the effect of doubling, tripling and quadrupling the distance of separation (as measured from planet's center). Consider the planet's surface to be a distance of one Earth-radius (1 Rplama). Use the following table to record data for whole-number multiples of Rane. Separation Force (fictional units) Distance 2 R 3 R 4 R 5 R 6 R 7 R 8 R 9 R 10 R 11 R 12 R 21.1 pianet planet pianet planet planet planet planet planet planet planet planet Use your data to complete the following sentences. If the separation distance between the moon and the planet is ... increased by a factor of 2, then the Fgrav is olecredsed by a factor of a. ...
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5) What is the gravitational force of attraction between the Earth and the Sun? 30 R2/0
1. In an experiment to discover the effect of centripetal force on velocity, an object of mass m was swung on the end of a string in a horizontal circular path of radius r. F = mv²ir [Equation 1] F = mv/r The string tension provided the centripetal force Fthat produced the centripetal acceleration and kept the object revolving in its circular path. The centripetal force was determined by using a spring scale or force sensor that measured the tension on the string. By timing the revolutions and calculating the distance traveled by the object, the velocity v of the object was determined.
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5) A 200g rock is stuck to a 35cm radius tire. The tire spinning so that the rock has a speed of 27 meters per second. Determine the centripetal force on the rock with units of newtons.
1. In an experiment to discover the effect of centripetal force on velocity, an object of mass m was swung on the end of a string in a horizontal circular path of radius r. F = mv²ir [Equation 1] F = mv/r The string tension provided the centripetal force Fthat produced the centripetal acceleration and kept the object revolving in its circular path. The centripetal force was determined by using a spring scale or force sensor that measured the tension on the string. By timing the revolutions and calculating the distance traveled by the object, the velocity v of the object was determined.