166. A small town's growth follows the model P(t)=:where p is the population in-0.211+1.7ethousands and t is the number of years after 2015.a.) What was the town's population in 2015? (Round to the nearest person.)b.) After how many years will the population double? Round to the nearest tenth of a year.c.) Determine all asymptotes for this function, even the ones that do not have meaning in context ofthe problem. Interpret any asymptote(s) that make sense in context.

Answered: Image /qna-images/answer/b33c1d45-2634-41e3-b3a4-5e265b2d27fb.jpg

Answered: 6. A small town's growth follows the…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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1 77% 12:25 PM + MathHW415b... CLAJJ FLUW Brian's Parents internet provider charges them $49.50 each month plus $6.75 for every gigabyte downloaded, where x is the number of gigabyte downloaded and y is the total monthly charge. Write a function that represents this relationship?
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MA.912.F.1.5 Date: Period: Callie and her friend Elena are reading through different novels they checked out from their school library last Tuesday. Callie's progress through her novel can be modeled by the function p(d) = -25d +318, where p(d) represents the number of pages remaining to be read and d is the number of days since receiving the book. Elena's progress through her novel is modeled by the graph below. АУ # Pages Left 400 350 300 250 200 * 150 100 50 (3275) (8,75) 2 3 4 5 6 7 # Days Part A. Which student's novel has more pages to read? 8 9 10 11 Part B. Assuming they both continue to read at a constant rate, which student will complete their novel first?
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A graphing calculator is recommended. Straight-line depreciation is a method for estimating the value of an asset (such as a piece of machinery) as it loses value ("depreciates") through use. Given the original price of an asset, its useful lifetime, and its scrap value (its value at the end of its useful lifetime), the value of the asset after t years is given by the formula for 0 ≤ t ≤ (Useful lifetime). (a) A farmer buys a harvester for $40,000 and estimates its useful life to be 20 years, after which its scrap value will be $4000. Use the formula above to find a formula for the value V of the harvester after t years, for 0 ≤ t ≤ 20. (Do not use commas in your answer.) V = Value = Price - (b) Use your formula to find the value of the harvester after 5 years. V(5) = No Solution (c) Graph the function found in part (a) on a graphing calculator on the window [0, 20] by [0, 40,000]. (Hint: Use x instead of t.) Help 40000 30000 Price (Scrap value) (Useful Lifetime) 20000 10000 10 Fill…

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