6. A random sample of 16 statistics exams was taken. The average score in the sample was 76.2 with avariance of 144. The 99% confidence interval for the true average exam score isA. 49.677 to 102.723C. 67.359 to 85.041B. 73.99 to 78.41D. 67.437 to 84.963

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Answered: 6. A random sample of 16 statistics…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One-Way Airfares The average one-way airfare from Pittsburgh to Washington D.C. is $236. A random sample of 19 one-way fares during a particular month had a mean of $208 with a standard deviation of $43. At α=0.05, is there sufficient evidence to conclude a difference from the stated mean?
2. A sample of six college basketball player had an average weight of 217 pounds with a sample standard deviation of 10 pounds. Find the 95% confidence interval of the true mean weight of all basketball player.
Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.7 kilograms with a sample standard deviation of 7.16 kilograms. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with a standard deviation of 5.90 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let 4, denote the mean weight lost on the low-carb diet and u, denote the mean weight lost on the low-fat diet. Use the a = 0.01 level and the TI-84 Plus calculator. Compute the -value. Round the answer to four decimal places. Determine whether to reject H0 State a conclusion
Two brands of batteries are tested, and their voltages are compared. The summary statistics follow. For sample 1, the sample size is 27; the population standard deviation is 0.3 volts and the mean is 9.2 volts. For sample 2, the sample size is 30; the population standard deviation is 0.1 volts and the mean is 8.8 volts. Is the mean of sample 1 smaller than the mean of sample 2? Using a significance level of 0.05. a) Identify the claim and state the hypotheses. b) What is the test statistics? Find the critical values (s). c) Make the decision to reject or not reject the null hypothesis and explain why. d) Graph your decision and include all the values. That is, the mean, the standard deviation, the critical value(s), the rejection region. e) Set up the formula with the correct numbers for the 95% confidence interval of the mean number of jobs.
Please answer all. Thank you. A national random sample of 20 NCAE Scores from 2010 is listed below. 29,26,13,23,23,25,17,22,17,19 12,26,30,30,18,14,12,26,17,18 Calculate the 95 percent confidence interval for the mean NCAE score if the sample standard deviation is about 5.9407. A.) between 18.22 and 23.48 B.) between 18.07 and 23.63 C.) between negative infinity and 23.15 D.) between negative infinity and 23.05 The value of z selected for constructing a given confidence interval is called A.) confidence B.) error C.) student D.) critical value
Car and Driver Magazine tested a random sample of 9 hybrid cars and found their MPG to be 42, 51, 39, 44, 52, 48, 51, 44, and 47. Construct a 95% confidence interval for the population variance.
do B AND C
A study of 4 bolts of carpet showed that their average length was 76.2 yards and the sample standard deviation was 5.6 yards. Which of the following is the 80% confidence interval for the mean length per bolt of carpet? O A. 75.8 to 76.6 O B. 72.62 to 79.78 O C. 71.61 to 80.79 D. 75.40 to 77.00
Researchers examined the bill color (in hue degree) of male and female zebra finches. Here are the summary statistics from the study. Sex N Mean Standard deviation Males 59 2.91 1.46 Females 60 7.42 2.48 How different are male and female zebra finches in bill color? The margin of error for a 95% confidence interval for the difference in mean bill color μF – μM (in hue degree) is
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Do men score lower on average compared to women on their statistics finals? Final exam scores of twelve randomly selected male statistics students and twelve randomly selected female statistics students are shown below. Male: 89 94 88 64 57 58 62 83 82 88 57 78 Female: 81 80 65 66 97 92 70 94 82 90 65 93 Assume both follow a Normal distribution. What can be concluded at the the a = 0.10 level of significance level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Ho: Select an answer Select an answer Select an answer v (please enter a decimal) H1: Select an answer v Select an answer v Select an answer ♥ (Please enter a decimal) b. The test statistic ? v = (please show your answer to 3 decimal places.) c. The p-value = d. The p-value is ? v a e. Based on this, we should Select an answer v the null hypothesis. f. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) O The results are…

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6. A random sample of 16 statistics exams was taken. The average score in the sample was 76.2 with a variance of 144. The 99% confidence interval for the true average exam score is A. 49.677 to 102.723 C. 67.359 to 85.041 B. 73.99 to 78.41 D. 67.437 to 84.963