6. A particle moving along a straight line has a velocity given by v = 4 − x², where v is the velocity in ft/sec and x is the position in ft. = 1 ft. (a = −6 ft/sec²) (a) Determine the acceleration of the particle at position x = (b) Determine the travel time from the origin to the position x = 1 ft. (t = 0.275 sec) (c) Show that the particle never arrives at position x = 2 ft. (t = ∞) 1 1 Hint: ±² = 1½ (2²±² + 2 + 2). 4 x 2-x

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter2: Graphical And Tabular Analysis
Section2.1: Tables And Trends
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This is a Dynamics question using differential equations

6. A particle moving along a straight line has a velocity given by v = 4 − x², where v is the velocity in
ft/sec and x is the position in ft.
= 1 ft. (a = −6 ft/sec²)
(a) Determine the acceleration of the particle at position x =
(b) Determine the travel time from the origin to the position x = 1 ft. (t = 0.275 sec)
(c) Show that the particle never arrives at position x = 2 ft. (t = ∞)
1
1
Hint: ±² = 1½ (2²±² + 2 + 2).
4 x
2-x
Transcribed Image Text:6. A particle moving along a straight line has a velocity given by v = 4 − x², where v is the velocity in ft/sec and x is the position in ft. = 1 ft. (a = −6 ft/sec²) (a) Determine the acceleration of the particle at position x = (b) Determine the travel time from the origin to the position x = 1 ft. (t = 0.275 sec) (c) Show that the particle never arrives at position x = 2 ft. (t = ∞) 1 1 Hint: ±² = 1½ (2²±² + 2 + 2). 4 x 2-x
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