6. A lightbulb will work until failure. Being a cheap Chinese import the lightbulb has a0.001 chance of failure each time you turn on the lightbulb. We can think of failurewhen you turn on the lights as a Geometric DistributionG. What is the Standard Deviation for number of turning on the lightbulb neededfor the bulb to stop working?H. What is the range of times to turn on a lightbulb before failure that are within 2standard deviations of the mean?

Answered: Image /qna-images/answer/434e3566-522e-462b-9bbc-aeaf7d841cda.jpg

Answered: 6. A lightbulb will work until failure.…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Approximate the population mean and standard deviation of age for males. By the way, we are subtractibg vertically to get the midpoints (ex: 0+10/2=5, 10+20/5=15).
One graph in the figure represents a normal distribution with mean u= 15 and standard deviation o = 2. The other graph represents a normal distribution with mean u=11 and standard deviation o = 2. Determine which graph is which and explain how you know. A B 11 15 ... Choose the correct answer below. O A. Graph A has a mean of u = 15 and graph B has a mean of u = 11 because a larger mean shifts the graph to the right. O B. Graph A has a mean of u = 11 and graph B has a mean of u= 15 because a larger mean shifts the graph to the left. O C. Graph A has a mean of u = 11 and graph B has a mean of u = 15 because a larger mean shifts the graph to the right. O D. Graph A has a mean of u = 15 and graph B has a mean of u = 11 because a larger mean shifts the graph to the left.
One graph in the figure represents a normal distribution with mean = 15 and standard deviation o = 2. The other graph represents a normal distribution with mean u = 7 and standard deviation o = 2. Determine which graph is which and explain how you know .. Choose the correct answer below. OA. Graph A has a mean of μ = 15 and graph B has a mean of µ = 7 because a larger mean shifts the graph to the left. OB. Graph A has a mean of µ = 15 and graph B has a mean of μ = 7 because a larger mean shifts the graph to the right. OC. Graph A has a mean of u = 7 and graph B has a mean of μ = 15 because a larger mean shifts the graph to the right. G D. Graph A has a mean of μ = 7 and graph B has a mean of µ = 15 because a larger mean shifts the graph to the left. 7 15 B M
Suppose that the speeds of cars travelling on California freeways are normally distributed with a mean of 63 0 miles hour miles tickets for cars with speeds exceeding 80 . The records show that exactly 5% of the speeds exceed this limit. Find the standard deviation of the speeds of cars travelling on California freeways. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place. hour miles hour The highway patrol's policy is to issue
Assume that adults have IQ score that are normally distributed with a mean of 100.4 and a standard deviation of 19.1. Find the probability that a randomly selected adult has an IQ greater than 130.7 (hint draw a graph.) the probability that a randomly selected adult from this group has an IQ greater than 130.7
complete the following details please
The average American gets a haircut every 34 days. Is the average smaller for college students? The data below shows the results of a survey of 15 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 23, 32, 38, 31, 39, 35, 25, 30, 36, 40, 27, 23, 32, 25 What can be concluded at the the a = 0.10 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ?v Select an answerv Hi: ?vSelect an answerv c. The test statistic ?v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is 2v a f. Based on this, we should Select an answerv the null hypothesis. g. Thus, the final conclusion is that.. O The data suggest the population mean is not significantly lower than 34 at a = 0.10, so there M 24 3. 4. 5 6. 7 EU
Please answer ASAP PLEASE
what estimate does the range rule of thumb give you for the standard deviation?
Suppose that the speeds of cars travelling on California freeways are normally distributed with a mean of 61 miles tickets for cars with speeds exceeding 80 The records show that exactly 1% of the speeds exceed this limit. Find the standard deviation of the speeds of hour cars travelling on California freeways. Carry your intermediate computations to at least four decimal places. Round your answer to at least one decimal place. miles hour X miles hour 5 . The highway patrol's policy is to issue
Assume that a randomly selected subject is given a bone density test. Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find P7, the 7th percentile. This is the bone density score separating the bottom 7% from the top 93%. Which graph represents P7? Choose the correct graph below. A. P7 The bone density score corresponding to P7 is (Round to two decimal places as needed.) B. A P7 2 C. ^ P7 Ly D. A P7
The problem below asks you to compare 4 different forecasting methodologies to determine which forecasting model results in the most accurate forecasts. Accuracy is determined by the lowest mean absolute deviation. Emergency calls to the 911 system of Greenville County for the past 24 weeks are shown below. Accurate forecasts are needed to determine the number of operators needed to staff the station. Week # of Calls 1 50 2 35 3 25 4 40 5 45 6 35 7 20 8 30 9 35 10 20 11 15 12 40 13 55 14 35 15 25 16 55 17 55 18 40 19 35 20 60 21 75 22 50 23 40 24 65 1. EXPONENTIAL SMOOTHING Compute the forecasts using α = .2. Calculate the MAD for weeks 4 through 24 only. Compute the forecasts using α = .6. Calculate the MAD for weeks 4 through 24 only. 2. SIMPLE LINEAR REGRESSION Use all of the data, weeks 1 - 24, to calculate the…

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