6. A hydrogen atom absorbs a photon of visible light, and its electron enters the n = 4 energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon. a) 20.4 x 10-¹⁹ J and 97.44 nm b) 4.09 x 10-1⁹ J and 486 nm c) 5.09 x 10-¹⁹ J and 4.86 nm d) 4.09 x 10-19 J and 386 nm
6. A hydrogen atom absorbs a photon of visible light, and its electron enters the n = 4 energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon. a) 20.4 x 10-¹⁹ J and 97.44 nm b) 4.09 x 10-1⁹ J and 486 nm c) 5.09 x 10-¹⁹ J and 4.86 nm d) 4.09 x 10-19 J and 386 nm
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Question 6: Photon Absorption in a Hydrogen Atom
#### Problem Statement:
A hydrogen atom absorbs a photon of visible light, and its electron enters the \( n = 4 \) energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon.
#### Choices:
a) \( 20.4 \times 10^{-19} \) J and \( 97.44 \) nm
b) \( 4.09 \times 10^{-19} \) J and \( 486 \) nm
c) \( 5.09 \times 10^{-19} \) J and \( 4.86 \) nm
d) \( 4.09 \times 10^{-19} \) J and \( 386 \) nm
#### Explanation:
To solve this problem, we need to use the relationship between the energy levels of the hydrogen atom and the energy of the absorbed photon. The energy change (\( \Delta E \)) when an electron transitions between energy levels in a hydrogen atom is given by:
\[ \Delta E = E_4 - E_i \]
Where \( E_4 \) is the energy of the \( n = 4 \) level and \( E_i \) is the energy level the electron transitioned from.
Additionally, the energy (\( E \)) of the absorbed photon can be related to its wavelength (\( \lambda \)) by the equation:
\[ E = \frac{hc}{\lambda} \]
Where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) Js)
- \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s)
- \( \lambda \) is the wavelength of the photon in meters
By matching the change in energy (\( \Delta E \)) with the given choices and using the respective equations, we can determine the correct option.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5cd8e990-ce02-47b6-a825-c11e2d2b1382%2Fcdad44d4-b579-40ca-b4a1-6e9bfa844a62%2Futp6ol_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 6: Photon Absorption in a Hydrogen Atom
#### Problem Statement:
A hydrogen atom absorbs a photon of visible light, and its electron enters the \( n = 4 \) energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon.
#### Choices:
a) \( 20.4 \times 10^{-19} \) J and \( 97.44 \) nm
b) \( 4.09 \times 10^{-19} \) J and \( 486 \) nm
c) \( 5.09 \times 10^{-19} \) J and \( 4.86 \) nm
d) \( 4.09 \times 10^{-19} \) J and \( 386 \) nm
#### Explanation:
To solve this problem, we need to use the relationship between the energy levels of the hydrogen atom and the energy of the absorbed photon. The energy change (\( \Delta E \)) when an electron transitions between energy levels in a hydrogen atom is given by:
\[ \Delta E = E_4 - E_i \]
Where \( E_4 \) is the energy of the \( n = 4 \) level and \( E_i \) is the energy level the electron transitioned from.
Additionally, the energy (\( E \)) of the absorbed photon can be related to its wavelength (\( \lambda \)) by the equation:
\[ E = \frac{hc}{\lambda} \]
Where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) Js)
- \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s)
- \( \lambda \) is the wavelength of the photon in meters
By matching the change in energy (\( \Delta E \)) with the given choices and using the respective equations, we can determine the correct option.
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