6. A hydrogen atom absorbs a photon of visible light, and its electron enters the n = 4 energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon. a) 20.4 x 10-¹⁹ J and 97.44 nm b) 4.09 x 10-1⁹ J and 486 nm c) 5.09 x 10-¹⁹ J and 4.86 nm d) 4.09 x 10-19 J and 386 nm

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### Question 6: Photon Absorption in a Hydrogen Atom

#### Problem Statement:
A hydrogen atom absorbs a photon of visible light, and its electron enters the \( n = 4 \) energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon.

#### Choices:
a) \( 20.4 \times 10^{-19} \) J and \( 97.44 \) nm

b) \( 4.09 \times 10^{-19} \) J and \( 486 \) nm

c) \( 5.09 \times 10^{-19} \) J and \( 4.86 \) nm

d) \( 4.09 \times 10^{-19} \) J and \( 386 \) nm

#### Explanation:
To solve this problem, we need to use the relationship between the energy levels of the hydrogen atom and the energy of the absorbed photon. The energy change (\( \Delta E \)) when an electron transitions between energy levels in a hydrogen atom is given by:

\[ \Delta E = E_4 - E_i \]

Where \( E_4 \) is the energy of the \( n = 4 \) level and \( E_i \) is the energy level the electron transitioned from.

Additionally, the energy (\( E \)) of the absorbed photon can be related to its wavelength (\( \lambda \)) by the equation:

\[ E = \frac{hc}{\lambda} \]

Where:
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) Js)
- \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s)
- \( \lambda \) is the wavelength of the photon in meters

By matching the change in energy (\( \Delta E \)) with the given choices and using the respective equations, we can determine the correct option.
Transcribed Image Text:### Question 6: Photon Absorption in a Hydrogen Atom #### Problem Statement: A hydrogen atom absorbs a photon of visible light, and its electron enters the \( n = 4 \) energy level. Calculate the change in energy of the atom and the wavelength (in nm) of the photon. #### Choices: a) \( 20.4 \times 10^{-19} \) J and \( 97.44 \) nm b) \( 4.09 \times 10^{-19} \) J and \( 486 \) nm c) \( 5.09 \times 10^{-19} \) J and \( 4.86 \) nm d) \( 4.09 \times 10^{-19} \) J and \( 386 \) nm #### Explanation: To solve this problem, we need to use the relationship between the energy levels of the hydrogen atom and the energy of the absorbed photon. The energy change (\( \Delta E \)) when an electron transitions between energy levels in a hydrogen atom is given by: \[ \Delta E = E_4 - E_i \] Where \( E_4 \) is the energy of the \( n = 4 \) level and \( E_i \) is the energy level the electron transitioned from. Additionally, the energy (\( E \)) of the absorbed photon can be related to its wavelength (\( \lambda \)) by the equation: \[ E = \frac{hc}{\lambda} \] Where: - \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \) Js) - \( c \) is the speed of light (\( 3.00 \times 10^8 \) m/s) - \( \lambda \) is the wavelength of the photon in meters By matching the change in energy (\( \Delta E \)) with the given choices and using the respective equations, we can determine the correct option.
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