6. A hoop (rotational inertia Į = MR² ) of mass 2.00 kg and radius 0.50 m is rolling at a center- of-mass speed of 2.50 m/s. An external force does 75.0J of a positive work on the hoop. (a) Calculate the initial total kinetic energy KE and (b) find the new speed of the hoop. (hint: W = AKE = KEF – KE , KE = KEtrans + KErot, w = v/R) %3D %3D %3D (a) KE = KErans + KErot =Mv2 %3D KEF = W + KE; %3D %3D (b)v, = %3D
6. A hoop (rotational inertia Į = MR² ) of mass 2.00 kg and radius 0.50 m is rolling at a center- of-mass speed of 2.50 m/s. An external force does 75.0J of a positive work on the hoop. (a) Calculate the initial total kinetic energy KE and (b) find the new speed of the hoop. (hint: W = AKE = KEF – KE , KE = KEtrans + KErot, w = v/R) %3D %3D %3D (a) KE = KErans + KErot =Mv2 %3D KEF = W + KE; %3D %3D (b)v, = %3D
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:6. A hoop (rotational inertia Į = MR² ) of mass 2.00 kg and radius 0.50 m is rolling at a center-
of-mass speed of 2.50 m/s. An external force does 75.0J of a positive work on the hoop. (a) Calculate the
initial total kinetic energy KE and (b) find the new speed of the hoop. (hint: W = AKE = KEF – KE , KE
= KEtrans + KErot, w = v/R)
%3D
%3D
%3D
(a) KE = KErans + KErot =Mv2
%3D
KEF = W + KE;
%3D
%3D
(b)v, =
%3D
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