6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3v EV: d(v) = 3 b. G is Eulerian G is regular
6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3v EV: d(v) = 3 b. G is Eulerian G is regular
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter12: Angle Relationships And Transformations
Section: Chapter Questions
Problem 28CR
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Question
![6. A connected graph with four edges and four vertices has two vertices of
degree two. Show that
a. G not Eulerian 3vEV: d(v) = 3
b. G is Eulerian G is regular
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce0315f7-0ef9-4269-b2de-e3ba61e8ca4f%2Ffc2fae3a-9de3-4991-acea-10dfc4378212%2F5trx2v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. A connected graph with four edges and four vertices has two vertices of
degree two. Show that
a. G not Eulerian 3vEV: d(v) = 3
b. G is Eulerian G is regular
%3D
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