6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3v e V : d(v) = 3 %3D C is Puulorion G js rogular
6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3v e V : d(v) = 3 %3D C is Puulorion G js rogular
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter12: Angle Relationships And Transformations
Section: Chapter Questions
Problem 28CR
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![6. A connected graph with four edges and four vertices has two vertices of
degree two. Show that
a. G not Eulerian 3vEV: d(v) = 3
b. G is Eulerian G is regular
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9e71c8e-2b98-4315-99ed-1ec969ee4365%2F7f341a6e-6c7b-4b01-b288-6612bbc8f847%2Fh07xgfl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. A connected graph with four edges and four vertices has two vertices of
degree two. Show that
a. G not Eulerian 3vEV: d(v) = 3
b. G is Eulerian G is regular
%3D
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