6.- A 100 V EMF is applied to an RC circuit with R 200 and a capacitance of 10-1 Farads. = a) Determine the charge q(t) of the capacitor if q(0) b) Find the current I(t) at any time t. = O at any time t. www C

A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?

You are working in an industrial plant. You have been instructed to double the capacitance connected to a machine. The markings on the capacitor, however, are not visible. The capacitor is connected to 560 volts and an ammeter indicates a current of 6 amperes flowing to the capacitor. What size capacitor should be connected in parallel with the existing capacitor? What is the minimum AC voltage rating of the new capacitor? What is the minimum DC voltage rating of the new capacitor? What is the minimum KVAR size that can be used in this installation?

4. In what form is the energy of a capacitor stored?

You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.

You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.

Can current flow through a capacitor?

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As discussed in your reading material, the MAIN reason for calculating a capacitance value is to adjust capacitor timing determine the nominal value of the capacitor check for short circuits check for open plates in the capacitor a. b. C. d.

Determine the total capacitance, total charge, individual voltage drop and charges across each capacitor. Use two decimal places for your answer. Put your answer for the individual voltage and charge for each capacitor in a table for faster checking. Thank you! Here are the values for the capacitors: C1 = 34 C6 = 29 C2 = 46 C7 = 38 C3 = 28 C8 = 23 C4 = 43 C9 = 32 C5 = 24 C10 = 23