Answered: 6. A 1.15 kg mass oscillates according… | bartleby

Related questions

Question

6. A 1.15 kg mass oscillates according to the equation x = 0.650 cos 7.40 t where x is in meters and t in
seconds. Determine (a) the amplitude, (b) the frequency, (c) the total energy, and (d) the kinetic
energy and potential energy when x= 0.260 m.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

please answer question d) for the follow up questions

Solution

by Bartleby Expert

Similar questions

9. An object is attached to a bottom of 3 identical spring that is set into oscillation motion with an amplitude of 40.2 cm. The maximum speed of the object is 27.9 m/s. If the spring constant of a single spring is 1.78 x 10° N/m, what is the mass of the object.
A 1.72 kg mass attached to an ideal spring oscillates horizontally with an amplitude of 2.48 m. The spring constant is 108.85 N/m. What is the period of the motion? Round off your final answer to two decimal places.
3. A 200g air glider is set up to move with almost no friction on a track. It has springs attached to both ends which give the system a combined spring constant of 30 N/m. At time t = 0, the glider has a velocity of 1.5 m/s 2 and is located at the equilibrium position. For this system, find the amplitude, period, angular frequency, and total energy, and write an equation of motion for the system.
A mass-spring system oscillates with an amplitude of 4.00 cm. If the spring constant is 241 N/m and the mass is 472 g, determine the mechanical energy of the system. Determine the maximum speed of the object. Determine the maximum acceleration.
3. A 20 g block is attached to a spring and oscillates at 2.0 Hz. At one instant, the block is at x = 5.0 cm and has a velocity v = -30 cm/s Find the amplitude and the period of the motion.
8. A pendulum with a length of 1.00 m is released from an initial angle of 15.0°. After 1 000 s, its amplitude has been reduced by friction to 5.50°. What is the value of b/2m?
3. A simple harmonic oscillator consists of a block attached to a spring with k = 200 N/m. The block slides on a frictionless surface, with equilibrium point x = 0 and amplitude 0.20 m. A graph of the block's velocity v as a function of time t is shown. The horizontal scale is set by t, = 0.20 s.What v (m/s) t (s) are -2n the period of the SHM the block's mass а. b. it's displacement at t = 0 it's acceleration at t = 0.10 s, and it's maximum kinetic energy? С. d. е.
2. A 100 gram mass is attached to a spring and undergoes simple harmonic motion with period of T=2 sec. If the total energy of the systenm is E= 5J, find (a) force constant k. and (b) the amplitude of motion 4.
The position of a 90 g oscillating mass is given by x(t)=A cos(10t−π/4)x(t)=A cos(10t−π/4), where ttt is in s and the amplitude A=4 cm. If necessary, round your answers to three significant figures. Determine The amplitude. The period. The spring constant. The phase constant.
A 507 g mass oscillates with an amplitude of 10.0 cm on a spring whose spring constant is 20.0 N/m. Determine:a. The period.b. The maximum speed.c. The total energy.
2. An object whose mass is 520 g is fastened to the end of a horizontal spring whose spring constant is 78 N/m. The object is pulled 5.0 cm from equilibrium and released. Assume no friction between the object and the floor. (a) What is the angular frequency and the period of oscillation? b) Write the specific equation of motion for this oscillating system, in the form x(t) A cos(cot + )
An undamped 1.20 kg1.20 kg horizontal spring oscillator has a spring constant of 39.4 N/m.39.4 N/m. While oscillating, it is found to have a speed of 3.86 m/s3.86 m/s as it passes through its equilibrium position. What is its amplitude ?A of oscillation?

SEE MORE QUESTIONS