6 – x2 If f(x) find: 5 + x2 ' f'(x) = %3D

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter4: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 3CC: If xis large, which function grows faster, f(x)=2x or g(x)=x2?
Question

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**Problem Statement:**

If \( f(x) = \frac{6 - x^2}{5 + x^2} \), find:

\[ f'(x) = \]

**Explanation:**

To find the derivative \( f'(x) \) of the given function, you can apply the Quotient Rule. The function \( f(x) \) is presented as a fraction with numerator \( 6 - x^2 \) and denominator \( 5 + x^2 \).

**Quotient Rule**: If you have a function \( f(x) = \frac{u(x)}{v(x)} \), its derivative \( f'(x) \) is given by:

\[
f'(x) = \frac{v(x)u'(x) - u(x)v'(x)}{(v(x))^2}
\]

Here, \( u(x) = 6 - x^2 \) and \( v(x) = 5 + x^2 \).

To find \( f'(x) \), calculate:

1. \( u'(x) = \) derivative of the numerator \( 6 - x^2 \).
2. \( v'(x) = \) derivative of the denominator \( 5 + x^2 \).

Substitute these derivatives into the Quotient Rule formula to find \( f'(x) \).
Transcribed Image Text:**Problem Statement:** If \( f(x) = \frac{6 - x^2}{5 + x^2} \), find: \[ f'(x) = \] **Explanation:** To find the derivative \( f'(x) \) of the given function, you can apply the Quotient Rule. The function \( f(x) \) is presented as a fraction with numerator \( 6 - x^2 \) and denominator \( 5 + x^2 \). **Quotient Rule**: If you have a function \( f(x) = \frac{u(x)}{v(x)} \), its derivative \( f'(x) \) is given by: \[ f'(x) = \frac{v(x)u'(x) - u(x)v'(x)}{(v(x))^2} \] Here, \( u(x) = 6 - x^2 \) and \( v(x) = 5 + x^2 \). To find \( f'(x) \), calculate: 1. \( u'(x) = \) derivative of the numerator \( 6 - x^2 \). 2. \( v'(x) = \) derivative of the denominator \( 5 + x^2 \). Substitute these derivatives into the Quotient Rule formula to find \( f'(x) \).
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