6) Use the process of completing the square to transform the General Form equation below into Graphing Form. 0 = x² + y° + 2x - 6y - 6

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### Completing the Square to Transform the General Form Equation to Graphing Form

6) Use the process of completing the square to transform the General Form equation below into Graphing Form.

\[ 0 = x^2 + y^2 + 2x - 6y - 6 \]

#### Steps to Solve:

1. **Group the x and y terms:**
   
   Rearrange the equation to group the x terms together and y terms together:

   \[ x^2 + 2x + y^2 - 6y = 6 \]
   
2. **Complete the square for the x terms:**
   
   - Take the coefficient of x, which is 2, divide it by 2 to get 1, and then square it to get 1.
   - Add and subtract 1 within the x group to complete the square:
     
     \[ x^2 + 2x + 1 - 1 \]
     
     So, the equation becomes:
     
     \[ (x + 1)^2 - 1 \]

3. **Complete the square for the y terms:**
   
   - Take the coefficient of y, which is -6, divide it by 2 to get -3, and then square it to get 9.
   - Add and subtract 9 within the y group to complete the square:
     
     \[ y^2 - 6y + 9 - 9 \]
     
     So, the equation becomes:
     
     \[ (y - 3)^2 - 9 \]

4. **Rewrite the equation in completed square form:**
   
   Combining these completed squares into a single equation:
   
   \[ (x + 1)^2 - 1 + (y - 3)^2 - 9 = 6 \]

5. **Simplify the equation:**
   
   Combine the constants on the right-hand side:
   
   \[ (x + 1)^2 + (y - 3)^2 - 10 = 6 \]
   
   So, the equation becomes:
   
   \[ (x + 1)^2 + (y - 3)^2 = 16 \]

Now, the equation \((x + 1)^2 + (y - 3)^2 = 16\) is in the standard graphing form of a circle equation \((x - h)^2
Transcribed Image Text:### Completing the Square to Transform the General Form Equation to Graphing Form 6) Use the process of completing the square to transform the General Form equation below into Graphing Form. \[ 0 = x^2 + y^2 + 2x - 6y - 6 \] #### Steps to Solve: 1. **Group the x and y terms:** Rearrange the equation to group the x terms together and y terms together: \[ x^2 + 2x + y^2 - 6y = 6 \] 2. **Complete the square for the x terms:** - Take the coefficient of x, which is 2, divide it by 2 to get 1, and then square it to get 1. - Add and subtract 1 within the x group to complete the square: \[ x^2 + 2x + 1 - 1 \] So, the equation becomes: \[ (x + 1)^2 - 1 \] 3. **Complete the square for the y terms:** - Take the coefficient of y, which is -6, divide it by 2 to get -3, and then square it to get 9. - Add and subtract 9 within the y group to complete the square: \[ y^2 - 6y + 9 - 9 \] So, the equation becomes: \[ (y - 3)^2 - 9 \] 4. **Rewrite the equation in completed square form:** Combining these completed squares into a single equation: \[ (x + 1)^2 - 1 + (y - 3)^2 - 9 = 6 \] 5. **Simplify the equation:** Combine the constants on the right-hand side: \[ (x + 1)^2 + (y - 3)^2 - 10 = 6 \] So, the equation becomes: \[ (x + 1)^2 + (y - 3)^2 = 16 \] Now, the equation \((x + 1)^2 + (y - 3)^2 = 16\) is in the standard graphing form of a circle equation \((x - h)^2
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