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6) Use Linear Property to find ( 1- 3 x4)' A) (1- 3 x4) %3D B) – 4x3 C) - 2 D) - 12 x3 7) Use Product Rule to find [(1 - 3 x4)(sin x) ] ' = A) -12 x3 (sin x) + (1 – 3 x4)(cos x) C) -12 x3 (cos x) + (1 – 3 x4)(cos x) 7) B) -12 x3 (sin x) + (1 – 3 x4)(sin x) D) -12 x3 (cos x) + (1 – 3 x4)(sin x) 8) Use Quotient Rule to find [(1 - 3 x4)/(sin x) ]' =, A) [-12 x3 (cos x) + (1 – 3 x4)(cos x) ]/ sin2 x B) [-12 x3 (sin x) - (1 – 3 x4)(cos x) ]/ sin2 x C) [-12 x3 (cos x) – (1 – 3 x4)(cos x) ]/ cos2 x D) [-12 x3 (sin x) – (1 – 3 x4)(cos x) ]/ cos2 x 8) 9) Use Power Rule to find [(1 – 3 x*)25 ] ' = A) -25(1 - 3x4)24 x3 C) -300(1 – 3 x*)100 x3 9) B) -12(1 - 3 x9)24 D) -300(1 - 3 x4)24 x3

6) Use Linear Property to find ( 1- 3 x4)' A) (1- 3 x4) %3D B) – 4x3 C) - 2 D) - 12 x3 7) Use Product Rule to find [(1 - 3 x4)(sin x) ] ' = A) -12 x3 (sin x) + (1 – 3 x4)(cos x) C) -12 x3 (cos x) + (1 – 3 x4)(cos x) 7) B) -12 x3 (sin x) + (1 – 3 x4)(sin x) D) -12 x3 (cos x) + (1 – 3 x4)(sin x) 8) Use Quotient Rule to find [(1 - 3 x4)/(sin x) ]' =, A) [-12 x3 (cos x) + (1 – 3 x4)(cos x) ]/ sin2 x B) [-12 x3 (sin x) - (1 – 3 x4)(cos x) ]/ sin2 x C) [-12 x3 (cos x) – (1 – 3 x4)(cos x) ]/ cos2 x D) [-12 x3 (sin x) – (1 – 3 x4)(cos x) ]/ cos2 x 8) 9) Use Power Rule to find [(1 – 3 x*)25 ] ' = A) -25(1 - 3x4)24 x3 C) -300(1 – 3 x*)100 x3 9) B) -12(1 - 3 x9)24 D) -300(1 - 3 x4)24 x3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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6) Use Linear Property to find ( 1 - 3 x4) ' A) (1– 3 x4) %3D B) – 4x3 C) - 2 D) - 12 x3 7) Use Product Rule to find [(1 – 3 x4)(sin x) ] ' = A) -12 x3 (sin x) + (1 – 3 x4)(cos x) C) -12 x3 (cos x) + (1 – 3 x4)(cos x) 7) B) -12 x3 (sin x) + (1 – 3 x4)(sin x) D) -12 x3 (cos x) + (1 – 3 x4)(sin x) 8) Use Quotient Rule to find [(1 – 3 x4)/(sin x) ] ' =, A) [-12 x3 (cos x) + (1 – 3 x4)(cos x) ]/ sin2 x B) [-12 x3 (sin x) – (1 – 3 x4)(cos x) ]/ sin2 x C) [-12 x3 (cos x) – (1 – 3 x4)(cos x) ]/ cos2 x D) [-12 x³ (sin x) – (1 – 3 x4)(cos x) ]/ cos2 x 8) 9) Use Power Rule to find [(1 – 3 x*)25 ] ' = A) -25(1 - 3 x4)24 x3 C) -300(1 – 3 x*)100 x3 9) B) -12(1 - 3 x9)24 D) -300(1 - 3 x4)24 x3
Transcribed Image Text:6) Use Linear Property to find ( 1 - 3 x4) ' A) (1– 3 x4) %3D B) – 4x3 C) - 2 D) - 12 x3 7) Use Product Rule to find [(1 – 3 x4)(sin x) ] ' = A) -12 x3 (sin x) + (1 – 3 x4)(cos x) C) -12 x3 (cos x) + (1 – 3 x4)(cos x) 7) B) -12 x3 (sin x) + (1 – 3 x4)(sin x) D) -12 x3 (cos x) + (1 – 3 x4)(sin x) 8) Use Quotient Rule to find [(1 – 3 x4)/(sin x) ] ' =, A) [-12 x3 (cos x) + (1 – 3 x4)(cos x) ]/ sin2 x B) [-12 x3 (sin x) – (1 – 3 x4)(cos x) ]/ sin2 x C) [-12 x3 (cos x) – (1 – 3 x4)(cos x) ]/ cos2 x D) [-12 x³ (sin x) – (1 – 3 x4)(cos x) ]/ cos2 x 8) 9) Use Power Rule to find [(1 – 3 x*)25 ] ' = A) -25(1 - 3 x4)24 x3 C) -300(1 – 3 x*)100 x3 9) B) -12(1 - 3 x9)24 D) -300(1 - 3 x4)24 x3
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