6- The next iterative value of the root of x²-4-0 using secant method, if the initial guesses are 3 and 4, is (A) 2.2857 (B) 2.5000 (C) 5.5000 (D) 5.7143 7- For finding the root of sinx-0 by the secant method, the following choice of initial guesses would not be appropriate. (A) and (B) and (C)-and (D) and 8- The Newton-Raphson method of finding roots of nonlinear equations falls under the category of (A) bracketing (B) open (C) random (D) graphical methods. 9. The Newton-Raphson method formula for finding the square root of a real number R from the equation x²-R=0 is, (A) X+1 3x (B) X1+1=34 (C) x+1=(x+ (D) X1+1=(3x) 10-The goal of forward elimination steps in the Gauss elimination method is to reduce the coefficient matrix to a (an). (A) diagonal (B) identity (C) lower triangular (D) upper triangular 11-Using Gauss elimination solution to 0.0030x+55.23x=58.12 6.239x1 -7.123x=47.23 Is (A) x1 = 26.66; x2 = 1.051 (B) x1 = 8.769; x2 = 1.051 (C) x1 = 8.800; x2 = 1.000 (D) x1 8.771; x2 = 1.052 12-Absolute error is defined as matrix. (A) Present Approximation - Previous Approximation (B) True Value - Approximate Value (C) abs (True Value - Approximate Value) (D) abs (Present Approximation - Previous Approximation)

6- The next iterative value of the root of x²-4-0 using secant method, if the initial guesses are 3 and 4, is (A) 2.2857 (B) 2.5000 (C) 5.5000 (D) 5.7143 7- For finding the root of sinx-0 by the secant method, the following choice of initial guesses would not be appropriate. (A) and (B) and (C)-and (D) and 8- The Newton-Raphson method of finding roots of nonlinear equations falls under the category of (A) bracketing (B) open (C) random (D) graphical methods. 9. The Newton-Raphson method formula for finding the square root of a real number R from the equation x²-R=0 is, (A) X+1 3x (B) X1+1=34 (C) x+1=(x+ (D) X1+1=(3x) 10-The goal of forward elimination steps in the Gauss elimination method is to reduce the coefficient matrix to a (an). (A) diagonal (B) identity (C) lower triangular (D) upper triangular 11-Using Gauss elimination solution to 0.0030x+55.23x=58.12 6.239x1 -7.123x=47.23 Is (A) x1 = 26.66; x2 = 1.051 (B) x1 = 8.769; x2 = 1.051 (C) x1 = 8.800; x2 = 1.000 (D) x1 8.771; x2 = 1.052 12-Absolute error is defined as matrix. (A) Present Approximation - Previous Approximation (B) True Value - Approximate Value (C) abs (True Value - Approximate Value) (D) abs (Present Approximation - Previous Approximation)

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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