6- The next iterative value of the root of x²-4-0 using secant method, if the initial guesses are 3 and 4, is (A) 2.2857 (B) 2.5000 (C) 5.5000 (D) 5.7143 7- For finding the root of sinx-0 by the secant method, the following choice of initial guesses would not be appropriate. (A) and (B) and (C)-and (D) and 8- The Newton-Raphson method of finding roots of nonlinear equations falls under the category of (A) bracketing (B) open (C) random (D) graphical methods. 9. The Newton-Raphson method formula for finding the square root of a real number R from the equation x²-R=0 is, (A) X+1 3x (B) X1+1=34 (C) x+1=(x+ (D) X1+1=(3x) 10-The goal of forward elimination steps in the Gauss elimination method is to reduce the coefficient matrix to a (an). (A) diagonal (B) identity (C) lower triangular (D) upper triangular 11-Using Gauss elimination solution to 0.0030x+55.23x=58.12 6.239x1 -7.123x=47.23 Is (A) x1 = 26.66; x2 = 1.051 (B) x1 = 8.769; x2 = 1.051 (C) x1 = 8.800; x2 = 1.000 (D) x1 8.771; x2 = 1.052 12-Absolute error is defined as matrix. (A) Present Approximation - Previous Approximation (B) True Value - Approximate Value (C) abs (True Value - Approximate Value) (D) abs (Present Approximation - Previous Approximation)
6- The next iterative value of the root of x²-4-0 using secant method, if the initial guesses are 3 and 4, is (A) 2.2857 (B) 2.5000 (C) 5.5000 (D) 5.7143 7- For finding the root of sinx-0 by the secant method, the following choice of initial guesses would not be appropriate. (A) and (B) and (C)-and (D) and 8- The Newton-Raphson method of finding roots of nonlinear equations falls under the category of (A) bracketing (B) open (C) random (D) graphical methods. 9. The Newton-Raphson method formula for finding the square root of a real number R from the equation x²-R=0 is, (A) X+1 3x (B) X1+1=34 (C) x+1=(x+ (D) X1+1=(3x) 10-The goal of forward elimination steps in the Gauss elimination method is to reduce the coefficient matrix to a (an). (A) diagonal (B) identity (C) lower triangular (D) upper triangular 11-Using Gauss elimination solution to 0.0030x+55.23x=58.12 6.239x1 -7.123x=47.23 Is (A) x1 = 26.66; x2 = 1.051 (B) x1 = 8.769; x2 = 1.051 (C) x1 = 8.800; x2 = 1.000 (D) x1 8.771; x2 = 1.052 12-Absolute error is defined as matrix. (A) Present Approximation - Previous Approximation (B) True Value - Approximate Value (C) abs (True Value - Approximate Value) (D) abs (Present Approximation - Previous Approximation)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Transcribed Image Text:6- The next iterative value of the root of x²-4-0 using secant method, if the initial guesses
are 3 and 4, is
(A) 2.2857
(B) 2.5000
(C) 5.5000
(D) 5.7143
7- For finding the root of sinx-0 by the secant method, the following choice of initial
guesses would not be appropriate.
(A) and
(B) and
(C)-and
(D) and
8- The Newton-Raphson method of finding roots of nonlinear equations falls under the
category of
(A) bracketing
(B) open
(C) random
(D) graphical
methods.
9. The Newton-Raphson method formula for finding the square root of a real number
R from the equation x²-R=0 is,
(A) X+1
3x
(B) X1+1=34
(C) x+1=(x+
(D) X1+1=(3x)
10-The goal of forward elimination steps in the Gauss elimination method is to reduce
the coefficient matrix to a (an).
(A) diagonal
(B) identity
(C) lower triangular
(D) upper triangular
11-Using Gauss elimination solution to
0.0030x+55.23x=58.12
6.239x1 -7.123x=47.23
Is
(A) x1 = 26.66; x2 = 1.051
(B) x1 = 8.769; x2 = 1.051
(C) x1 = 8.800; x2 = 1.000
(D) x1 8.771; x2 = 1.052
12-Absolute error is defined as
matrix.
(A) Present Approximation - Previous Approximation
(B) True Value - Approximate Value
(C) abs (True Value - Approximate Value)
(D) abs (Present Approximation - Previous Approximation)
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