(6) Prove Darboux's Theorem: If f is differentiable on all of R and a and b are any real numbers such that a < b, and f'(a) < f'(b), then for every real number y such that f'(a) < y < f'(b), there is ace (a,b) such that f'(c) = y. (In other words, Darboux's Theorem says that the deritvative of a function satisfies the conclusion of the IVT.) Tips: First consider the case where f'(a) < 0, f'(b) > 0 and y = 0. For this case, by the Extreme Value Theorem f attains its minimum value on [a, b] at some point c e [a, b]. Prove that c + a and c + b (using that f'(a) < 0 and f'(b) > 0), and then apply the Min-Max Theorem. For the general case, apply the first case to the function h(x) := f(x) – yæ.

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real analysis

**Proving Darboux's Theorem**

**Problem Statement:**  
Prove Darboux's Theorem: If \( f \) is differentiable on all of \(\mathbb{R}\) and \( a \) and \( b \) are any real numbers such that \( a < b \), and \( f'(a) < f'(b) \), then for every real number \( y \) such that \( f'(a) < y < f'(b) \), there is a \( c \in (a, b) \) such that \( f'(c) = y \). In other words, Darboux's Theorem says that the derivative of a function satisfies the conclusion of the Intermediate Value Theorem (IVT).

**Tips for Proving the Theorem:**

1. **Initial Consideration:**  
   - First, consider the case where \( f'(a) < 0 \), \( f'(b) > 0 \), and \( y = 0 \).
   - By the Extreme Value Theorem, \( f \) attains its minimum value on \([a, b]\) at some point \( c \in [a, b] \).
   - Prove that \( c \neq a \) and \( c \neq b \) using the fact that \( f'(a) < 0 \) and \( f'(b) > 0 \).
   - Apply the Min-Max Theorem.

2. **General Case:**
   - For the general case, apply the first case to the function \( h(x) := f(x) - yx \).

This problem provides a conceptual understanding of how derivatives behave according to Darboux's Theorem, illustrating the Intermediate Value Property with derivatives.
Transcribed Image Text:**Proving Darboux's Theorem** **Problem Statement:** Prove Darboux's Theorem: If \( f \) is differentiable on all of \(\mathbb{R}\) and \( a \) and \( b \) are any real numbers such that \( a < b \), and \( f'(a) < f'(b) \), then for every real number \( y \) such that \( f'(a) < y < f'(b) \), there is a \( c \in (a, b) \) such that \( f'(c) = y \). In other words, Darboux's Theorem says that the derivative of a function satisfies the conclusion of the Intermediate Value Theorem (IVT). **Tips for Proving the Theorem:** 1. **Initial Consideration:** - First, consider the case where \( f'(a) < 0 \), \( f'(b) > 0 \), and \( y = 0 \). - By the Extreme Value Theorem, \( f \) attains its minimum value on \([a, b]\) at some point \( c \in [a, b] \). - Prove that \( c \neq a \) and \( c \neq b \) using the fact that \( f'(a) < 0 \) and \( f'(b) > 0 \). - Apply the Min-Max Theorem. 2. **General Case:** - For the general case, apply the first case to the function \( h(x) := f(x) - yx \). This problem provides a conceptual understanding of how derivatives behave according to Darboux's Theorem, illustrating the Intermediate Value Property with derivatives.
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