6 points In guinea pigs, black coat (B) is dominant over albino (b), and rough skin (R) is dominant over smooth (r). A black and rough guinea pig is crossed with an albino and rough and produces the following progeny: 13 black rough, 16 albinos rough, 6 black and smooth, and 5 albinos smooth. According to these observed phenotypic frequencies, the genotypes of the parent with black coat and rough skin must be type your answer... and the parent with albino coat and rough skin must be type your answer... Therefore, the expected frequencies in the offspring should be: Black coat and rough skin is type your answer... Black coat and smooth skin is type your answer... Albino coat and rough skin is type your answer... Albino coat and smooth skin is type your answer... To prove your hypothesis, you conducted a chi-square test and calculated chi-square of type your answer... chi-square value of type your answer... Therefore, you type your answer... Using a critical p-value of 0.05, you have a theoretical your null hypothesis.

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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6 points
In guinea pigs, black coat (B) is dominant over albino (b), and rough skin (R) is dominant over smooth (r). A black and rough guinea pig is crossed with an albino and rough and
produces the following progeny: 13 black rough, 16 albinos rough, 6 black and smooth, and 5 albinos smooth. According to these observed phenotypic frequencies, the
genotypes of the parent with black coat and rough skin must be type your answer... and the parent with albino coat and rough skin must be
type your answer...
Therefore, the expected frequencies in the offspring should be:
Black coat and rough skin is type your answer...
Black coat and smooth skin is type your answer...
Albino coat and rough skin is type your answer...
Albino coat and smooth skin is type your answer...
To prove your hypothesis, you conducted a chi-square test and calculated chi-square of type your answer...
chi-square value of type your answer...
Therefore, you type your answer...
Using a critical p-value of 0.05, you have a theoretical
your null hypothesis.
Transcribed Image Text:6 points In guinea pigs, black coat (B) is dominant over albino (b), and rough skin (R) is dominant over smooth (r). A black and rough guinea pig is crossed with an albino and rough and produces the following progeny: 13 black rough, 16 albinos rough, 6 black and smooth, and 5 albinos smooth. According to these observed phenotypic frequencies, the genotypes of the parent with black coat and rough skin must be type your answer... and the parent with albino coat and rough skin must be type your answer... Therefore, the expected frequencies in the offspring should be: Black coat and rough skin is type your answer... Black coat and smooth skin is type your answer... Albino coat and rough skin is type your answer... Albino coat and smooth skin is type your answer... To prove your hypothesis, you conducted a chi-square test and calculated chi-square of type your answer... chi-square value of type your answer... Therefore, you type your answer... Using a critical p-value of 0.05, you have a theoretical your null hypothesis.
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