6 — х — а? if x<1 { - - Let f(x) = 2х — 3 if x > 1 - Calculate the following limits. Enter "DNE" if the limit does not exist. lim f(x) x →1- lim f(æ) = x →1+ lim x →1 f(x) =
6 — х — а? if x<1 { - - Let f(x) = 2х — 3 if x > 1 - Calculate the following limits. Enter "DNE" if the limit does not exist. lim f(x) x →1- lim f(æ) = x →1+ lim x →1 f(x) =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![Let \( f(x) =
\begin{cases}
6 - x - x^2 & \text{if } x \leq 1 \\
2x - 3 & \text{if } x > 1
\end{cases} \)
Calculate the following limits. Enter "DNE" if the limit does not exist.
1. \( \lim_{x \to 1^-} f(x) = \) [Box for answer]
2. \( \lim_{x \to 1^+} f(x) = \) [Box for answer]
3. \( \lim_{x \to 1} f(x) = \) [Box for answer]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcaf4173b-b755-4e87-930d-0e5a2f72e342%2F2586291e-ba08-491a-a607-87d57cdca76c%2Fzy3t7r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let \( f(x) =
\begin{cases}
6 - x - x^2 & \text{if } x \leq 1 \\
2x - 3 & \text{if } x > 1
\end{cases} \)
Calculate the following limits. Enter "DNE" if the limit does not exist.
1. \( \lim_{x \to 1^-} f(x) = \) [Box for answer]
2. \( \lim_{x \to 1^+} f(x) = \) [Box for answer]
3. \( \lim_{x \to 1} f(x) = \) [Box for answer]
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