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(6) f(n) = 2-√√uti n-3. tim f(n) 13+ lim 473- 드 Hence, f(u) = lim #10+ = f(") NOW (im brot (im h+ot (1 lim hot 2-√√√(3+6)+1 h ㅗ 4. But f(n) at n=3 (im h+0+ 2-√√3-b)+1 (-h) 4 2√4th 1 2 Hence, f() has continuity के ईसक √ (4-6) · (4). (-1) नन (6y Lhopital (aw) hay nemovable Redefine f(a) as f(u) (o form) 3 not defined. ( form) discontinuity at 1²3 45 2-√√uti 1-3 иг 1 if n #3 it n = 3

(6) f(n) = 2-√√uti n-3. tim f(n) 13+ lim 473- 드 Hence, f(u) = lim #10+ = f(") NOW (im brot (im h+ot (1 lim hot 2-√√√(3+6)+1 h ㅗ 4. But f(n) at n=3 (im h+0+ 2-√√3-b)+1 (-h) 4 2√4th 1 2 Hence, f() has continuity के ईसक √ (4-6) · (4). (-1) नन (6y Lhopital (aw) hay nemovable Redefine f(a) as f(u) (o form) 3 not defined. ( form) discontinuity at 1²3 45 2-√√uti 1-3 иг 1 if n #3 it n = 3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(6) f(n) = 2-√√uti n-3. tim f(n) M3+ lim 473- f(u) = Hence = = NOW lim #10+ f(a) C lim brot lim h+ot 2 -4. lim hot 2-√√√(3+6)+1 h But t() at n=3 (im h+o+ 2-√√(3-5)+1 (h) 1 2√4th 2 2 उसका (4) (6y Lihopital (aw) hay Redefine f(a) f(u) 4-h (o form) (o form) 3 not defined. nemorable discontinuity at n=3 f(a) as 2-Juti 1-3 Hence, f(n) has continuity at n=3 C if "#3 it n = 3 n=3
Transcribed Image Text:(6) f(n) = 2-√√uti n-3. tim f(n) M3+ lim 473- f(u) = Hence = = NOW lim #10+ f(a) C lim brot lim h+ot 2 -4. lim hot 2-√√√(3+6)+1 h But t() at n=3 (im h+o+ 2-√√(3-5)+1 (h) 1 2√4th 2 2 उसका (4) (6y Lihopital (aw) hay Redefine f(a) f(u) 4-h (o form) (o form) 3 not defined. nemorable discontinuity at n=3 f(a) as 2-Juti 1-3 Hence, f(n) has continuity at n=3 C if "#3 it n = 3 n=3
(c) f(n) = lim → (4) + lim ^(-)- Hence, f(n) f(^) n+2 (₁+i) ² 2 3 lim hot Iim hyot h10+ tim hoot f(u) has +a th+2 (4th+1) √htt h 14-h+2 (-1-h+1)2 1-h 52 infinite discontinuity at nant.
Transcribed Image Text:(c) f(n) = lim → (4) + lim ^(-)- Hence, f(n) f(^) n+2 (₁+i) ² 2 3 lim hot Iim hyot h10+ tim hoot f(u) has +a th+2 (4th+1) √htt h 14-h+2 (-1-h+1)2 1-h 52 infinite discontinuity at nant.
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