6) Find the equation of the osculating plane of the helix x = sin 3t, y = 2t, z = cos 3t at the point (–1, T, 0).

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Q: Find the equation of the osculating plane of the helix x = 3t, y = sin 2t, z = cos 2t at the point…

A: Given the helix rt=3t,sin2t,cos2t. At t=π2, we get rπ2=3π2,0,-1.…

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Q: Find the equation of the osculating plane of the helix x = sin 2t, y = t, z = cos 2t at the point…

A: The helix is given as x=sin 2t, y=t, z=cos 2t. We have to find the equation of the osculating plane…

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A: